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Math 4024 congruency again :P
- Thread starter ailg1996
- Start date
. .- Messages
- 202
- Reaction score
- 118
- Points
- 53
first question part (a)
(4/10)^2 = 16/100
16: 8cm^3
100: x cm^3
cross multiply
800cm = 16x
800/16 = 50 cm^3 is area of triangle ABC
(b)
(10/6)^2 = 100/36
100: 50
36: x
cross multiply
(50x36)/100 = x
cancel fifty
36/2 = x
18 = x
(c)
(6/6)^2
18 : 36cm^3
x : 36
x= 18x36/36
cancel 36
x= 18
(4/10)^2 = 16/100
16: 8cm^3
100: x cm^3
cross multiply
800cm = 16x
800/16 = 50 cm^3 is area of triangle ABC
(b)
(10/6)^2 = 100/36
100: 50
36: x
cross multiply
(50x36)/100 = x
cancel fifty
36/2 = x
18 = x
(c)
(6/6)^2
18 : 36cm^3
x : 36
x= 18x36/36
cancel 36
x= 18
- Messages
- 202
- Reaction score
- 118
- Points
- 53
im trying to do the second one but its confusing... :S are we supposed to find the ratios of the triangles successively? like start from top and work down.
(dont take me srsly, im taking a guess... but correct me if im wrong)
if thats right then: ratio between XPR and PRQ is (1/3) which combine together to make XQR(1+3).
ratio between XQR and QRZ is (2/3)
so if XQR is 4 than to find QRZ:
4 : 2
x : 3
2x=12
x=6
QYZ area is 1/3 of PRQ so its 1.
The ratio between QYZ and QRZ is 1/6. (???)
(dont take me srsly, im taking a guess... but correct me if im wrong)
if thats right then: ratio between XPR and PRQ is (1/3) which combine together to make XQR(1+3).
ratio between XQR and QRZ is (2/3)
so if XQR is 4 than to find QRZ:
4 : 2
x : 3
2x=12
x=6
QYZ area is 1/3 of PRQ so its 1.
The ratio between QYZ and QRZ is 1/6. (???)