• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics paper 4 helper

Messages
380
Reaction score
2
Points
26
Guys if anyone have any doubt then you could post it here as I can help you solving It
and give you some clues. I can easily help you
Also we could discuss the exam together after we finish
:beer:
 
Messages
18
Reaction score
0
Points
0
specimen 2011

heey ,, i really need help in specimen 2011 in the following Q's
Q1
Q2-(f)
Q4-(f)&(g)
Q5-(d)
Q6-(C)
 
Messages
205
Reaction score
13
Points
28
I dunno

Haven't really been through both papers so can't give you a reply to that :(
 
Messages
380
Reaction score
2
Points
26
Here you go IGCSE28
a)i)You just need to multiply the 20 000 000 into 12 to find the actual distance
Next mark, you get for converting your answer to km as the answer you found in first step is in cm(divide it by 100 000, 100 for cm to m and 1000 for m to km)

a)ii)Here there are three steps
First convert the map scale to area map(1^2:(20 000 000)^2)
Next find the answer by multiplying(4*10^14)*13 to get the actual distance
Lastly convert your answer to km2 as your answer is in cm2(divide it by 100 000*100 000)

b)i)the first mark you get is to convert one of numbers to the other unit to get the same units(1580km 158 000 000)
The second mark is for finding the ratio in the simplest form 31.6:158 000 000 to 1:5 000 000(n=5 000 000)

b)ii)First mark for the knowledge of the formula(distance/time)
Second mark for answering get the time(14 03 - 11 55 = 2 08)
Next mark for writing the time in numbers as shown 2+8/(60min)=2.13333333333333333hour
last mark for finding the answer 1580/2.1333333333=740.625km/hour

2)f)deals with a shear, you can multiply the transformation matrix into the points A,B,C
(1 0)(2 3 5)
(-1 1)(1 3 1)
A shear will always be of this format (1 0) or this one (1 k)(depends on which line is invarient)
(k 1) (0 1)
ii) Since 0 is the y axis part in the shear and it doesnt change so it is the y axis which is invarient
1
k is the scale factor so the scale factor is the -1
There the discription could be Shear with scale factor -1 and yaxis is the invarient line.

4f)i) p is vertical line so there is no any x-coordinate whereas p is half the value of DB as DB is 2p
Therfor the coordinate would be ( 0 )
(24)
F)ii)here x-coordinate is 7 as you need to move 7 units to your right and the y-coordinate is -24 as it goes down opposite to p and only
half the value of p
Therefore the matrix will be( 7 )
(-24)
g)this moves up to B as the value is 48 and then right to E by 14 units
There you could find that it is a right angle triangle in which you will have to find the hypotenuse using the Pythogoras theorm
square root of 14^2+48^2.

5)d)You just need to write the values of x-coordinates in which they make a line that is of negative gradient
(Note: A negative gradient line will make an obtuse angle with the Xaxis line on the upper side)
So the values would be from 0-6

6)C)I am writing it to you in steps
105/x-105/(x+4)=0.8
then make this fraction as single fraction
(105(x+4)-105x)/x(x+4)=0.8
Then simlify it by shifting the 0.8 to the denominator and x(x+4) to the other side

Hope this helped.
 
Messages
380
Reaction score
2
Points
26
Guys you could ask me more I could even give you notes, you just ask
Thats why its called mathematics helper
 
Messages
380
Reaction score
2
Points
26
Here you go test128
c)First convert the 1.3mm to m you will get it as 0.0013
you already have height of the segment and the total area of the segment
so you need to find the radius
0.0013*pie*r^2=2 and then you make r as the subject of the formula and find the radius

d)First you need to get the total area that is 50.4/0.12=420
The next step is to find the perimeter, so as you in the diagram in the previous page that you 2sides of length 0.8
and the below one only is 1.2 and so the total will be 0.8+0.8+1.2=2.8
If you multiply the length which you have to find into the total perimeter, you will get the area
so you have the area and the perimeter you need to find the length
Here you go 420/2.8=150(this is the answer)


Hope this helped.(Good luck for your tommorow's examination)
 
Messages
10
Reaction score
2
Points
13
umm , whats the difference between " shear " and " stretch" and how do you know if its a horizontal shear/stretch or vertical shear/stretch ??
+ do u know any easy method to memorize all the volume and area formulas ?
+ in cumulative frequency qs, when its 1<x<=6 and the cumulative frequency of that interval is 2, do we plot the point (1,2) or (6,2) ??
PLEASE ANSWER ASAP !! i need to pass xD
 
Messages
205
Reaction score
13
Points
28
Help's here

Candi00 said:
umm , whats the difference between " shear " and " stretch" and how do you know if its a horizontal shear/stretch or vertical shear/stretch ??
+ do u know any easy method to memorize all the volume and area formulas ?
+ in cumulative frequency qs, when its 1<x<=6 and the cumulative frequency of that interval is 2, do we plot the point (1,2) or (6,2) ??
PLEASE ANSWER ASAP !! i need to pass xD
Go to: http://www.xtremepapers.me/forums/viewtopic.php?f=24&t=6947
And the point you need to plot is (6,2)

Hope that helped !!! :)

Cheers !!! :good:
 
Messages
380
Reaction score
2
Points
26
Welcome
Ask me in anytime
Good luck for your tommorows examination
If you have more,then ask
 
Messages
2
Reaction score
0
Points
0
hey ok im damn scared, what exactly is specimen 2011?any relationship to the exercises in paper 4 2011? and is there a markscheme for it? if not PLEASE help me in question 9, pls pls pls and HUGE thanks to anybody that'll help.
cheers, waiting :/
 
Messages
2
Reaction score
0
Points
0
thanks for the markscheme.. A LOT...but...i still dont get how they did 9 c)....help?pls? :(, onli i) nd ii) i cant get the 10/3 nd the 32/3 .....
 
Messages
18
Reaction score
0
Points
0
sorry to bother you againn , can u wxpalin specimen 2011 Q8(a)& (b)
and i reallly need help in sequences to find the nth valuee :(
 
Messages
205
Reaction score
13
Points
28
Solution

The question states: ‘The total number of one centimetre lines in the first n diagrams is given by the expression’.

2/3 x n^3 + f x n^2 + g x n

So, when n = 1, you have to read through the table in Part 9 (b) and find the number of 1cm lines in the first diagram, which is 4.

Now equate and replace n with 1 at the same time equaling the expression to 4 since this is what it should give.

2/3 x 1^3 + f x 1^2 + g x 1 = 4
2/3 + f + g = 4
f + g = 4 – 2/3
f + g = 10/3

Good Luck !!! :D

Cheers !!! :good:
 
Top