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Who's giving paper 6 this year?
I need some doubt clearance !
I need some doubt clearance !
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In normal distribution you should havesyed1995 i need to know where in normal distribution, do we have to do 1-ans
got itIn normal distribution you should have
i) Z < *****
where ***** is POSITIVE number and sign between Z and Number is of smaller than. If its not, then we will subtract answer from 1.
What ?? .... it has to be 9!/2!*2!Find the number of different ways that the 9 letters of the word HAPPINESS can be arranged in
a line.
in the markscheme, it dosent allow 9!/2!*2!
(Answer: 90720)
This means that your final answer must be the given value instead of the calculation given . There is not 1 other way u could possibly solve this questionyup, but see the ms says not this.. look
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_ms_62.pdf
Question 4, (i)
ohk yeah point, i spent like an hour trying to do it the other way thanks!This means that your final answer must be the given value instead of the calculation given . There is not 1 other way u could possibly solve this question
Do you know how to change P(X < ****) to P(Z < ***) ?http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_62.pdf
Question 6, (i), in the markscheme, why did they take z as -1.282?
shouldn't we take the value for 0.1 as it says 10% ?
Z=X-Mean/Standard deviationhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_62.pdf
Question 6, (i), in the markscheme, why did they take z as -1.282?
shouldn't we take the value for 0.1 as it says 10% ?
Find the number of different ways that the 9 letters of the word HAPPINESS can be arranged in
a line.
in the markscheme, it dosent allow 9!/2!*2!
(Answer: 90720)
nope,you're notam i the only one who finds permutation and combination ANNOYING and HARD !
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