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Mathematics: Post your doubts here!

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Can someone help me in this Q9).c.
1) u hv to make simultaneous eqns.
2)
a) 8a + 4b + 2 = 12 (8 comes from cubing 2 and, 4 frm squaring 2, and the 2 is the nth term we use, 12 comes frm 9 +3)
b) 27a + 9b + 3 = 30 (27 comes frm cubing 3, 9 frm squaring 3, thats cuz nth term is 3, 30 comes from 18 + 9 + 3)
3) reorder the eqns.
a) 8a + 4b = 10
b) 27a + 9b = 27
4) solve the simultaneous eqn.
5) answers: a= 0.5 and b = 1.5
hope it helps !!!
best of luck !! :D
 

Maz

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1) u hv to make simultaneous eqns.
2)
a) 8a + 4b + 2 = 12 (8 comes from cubing 2 and, 4 frm squaring 2, and the 2 is the nth term we use, 12 comes frm 9 +3)
b) 27a + 9b + 3 = 30 (27 comes frm cubing 3, 9 frm squaring 3, thats cuz nth term is 3, 30 comes from 18 + 9 + 3)
3) reorder the eqns.
a) 8a + 4b = 10
b) 27a + 9b = 27
4) solve the simultaneous eqn.
5) answers: a= 0.5 and b = 1.5
hope it helps !!!
best of luck !! :D
I had already gotten it.Hence, i deleted it. Thanks anyway.
 
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Guyz .. please help ! i dont understand how to find the nth term of a sequence with different differences ..?
For example ..
1, 2, 4, 8, 16 …… please help !
well, the nth term can be found using the formula An+_b
Where A is the difference in the numbers
example:
5,7,9,11..etc..
to find the A, you subtract the numbers to get a COMMON difference
that difference is A; in this case 2 (7-5),(9-7),..
Next, B, is how much to get to the first number of the sequence
that means how much 2 has to get to 5, which is 3
so the nth term(formula) is 2n+3
hope that helped
 
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