Mathematics: Post your doubts here!

[ZaqZainab]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_22.pdf

the first question can u please explain

okay so here we know what C= 36.9
and we know that this is a right angles triangle
and now we know B=90
Sum of angles in a triangle is 180 so
180-(36.9+90)=53.1
Got the answer Yay

 

[ZaqZainab]

Salams. I have a doubt if someone can plz help.
Well it just counts 1 mark however i dont know how to do it for all cases.
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_1.pdf
its question 16, b)
3^x=1/81

Tks.

And now you know how the steps are and you have got your answer you can check your answer by
log((1/81))/log(3) which will give you -4

 

[Anonimous12345]

Here I come with other doubt.
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_3.pdf
Here in question nr 5b) it gives me answer)11.7 .
However the ms says 14.3

It should be:
TAN(55)=AX / 10 (=)
(=) tan (55) x 10 = AX (=)
(=) 11.7 = AX //

Whats missing here? Tks .

 

[Anonimous12345]

And now you know how the steps are and you have got your answer you can check your answer by
log((1/81))/log(3) which will give you -4

It turns out to be really easy then. Thank you so much =)

 

[Rockzstar]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_22.pdf

Please Explain 16 B

 

[tweetie]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_43.pdf
q 7a
q- 9c
q 11a (v)
PLEASE HELP ASAP

 

[notnek01]

Here I come with other doubt.
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_3.pdf
Here in question nr 5b) it gives me answer)11.7 .
However the ms says 14.3

It should be:
TAN(55)=AX / 10 (=)
(=) tan (55) x 10 = AX (=)
(=) 11.7 = AX //

Whats missing here? Tks .

Your working is fine so I don't know why you're getting 11.7.

tan(55) x 10 = 14.3 (3sf)

Can you post exactly what buttons you are pressing on your calculator?

 

[ZaqZainab]

It turns out to be really easy then. Thank you so much =)

You are welcome but you need to provide the workings too so you should just use this to check

 

[notnek01]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_22.pdf

Please Explain 16 B

The position vector of M is the vector O->M.

O->M = O->C + C->P + 1/2 P->Q.

= c + 1/2 a + P->Q.

You an use your answer to part (a) to complete the question.

 

[ZaqZainab]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_22.pdf

Please Explain 16 B

Position vector means from O so they are basically asking what is o to m
which is OA+AQ+QM
OA=a
AQ=1/2c
AND QM= 1/2 PQ which you found earlier
which is 1/2a-1/2c=PQ
now we have a+(1/2)c+(1/2a-1/2c)/2
get it ?? and then simplify

 

[notnek01]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_43.pdf
q 7a
q- 9c
q 11a (v)
PLEASE HELP ASAP

7a) How much of the tree have you drawn? What specifically are you having trouble with?

9c) fg(x) = f(g(x)) = f((x+2)^2) = 3(x+2)^2 + 1

Can you simplify this?


11a) This is a hard question. 2+4+6+...+800 = 2(1+2+3+...+400)

Does this make sense? You can use the formula given in (ii) to find the number in the brackets.

 

[notnek01]

Position vector means from O so they are basically asking what is o to m
which is OA+AQ+QM
OA=a
AQ=1/2c
AND QM= 1/2 PQ which you found earlier
which is 1/2a-1/2c=PQ
now we have a+(1/2)c+(1/2a-1/2c)/2
get it ?? and then simplify

You made a mistake: QM = -1/2 PQ

It's simpler to go clockwise around the shape instead of anticlockwise like you did.

 

[Anonimous12345]

Your working is fine so I don't know why you're getting 11.7.

tan(55) x 10 = 14.3 (3sf)

Can you post exactly what buttons you are pressing on your calculator?

Well I used another calculator and it gave me 14.3 .. So i conclude the other isn´t reliable . Sorry ! tks

 

[Rockzstar]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_22.pdf

Question 8 Plz explain

 

[ZaqZainab]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_22.pdf

Question 8 Plz explain

8a will be the point were the lines are intersecting
b will be you have to find the difference between the line as 0.5

 

[Rockzstar]

8a will be the point were the lines are intersecting
b will be you have to find the difference between the line as 0.5

but there are 3 points in B na ?

 

[ZaqZainab]

but there are 3 points in B na ?

Nope 2 points one from cos and one from sin

 

[Rockzstar]

Nope 2 points one from cos and one from sin

still unable to find it

 

[Rockzstar]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_22.pdf

plz explain question 16

 

[tiki-taka]

Sum1 please du dis....

23/O/N/12