Mathematics: Post your doubts here!

[notnek01]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w05_ms_2.pdf

Please Explain q)8

M->A is half of C->A.

C->A = -c + a

So M->A = 1/2 (-c + a) - -1/2 c + 1/2 a

 

[Ahmed Al Hilali]

2) Have you tried using tracing paper. The locus is the path that D moves as it is rotated.

This is an arc centre B, radius BD.


2) I've never seen this question in IGCSE and it doesn't really seem like a modern IGCSE question. I can help you with it if I can see the paper first.


3) 'The glass can be filled with water from the jar exactly 216 times.' This means that the volume factor = 216.

Scale factor = cube root(volume factor) = cube root (216) = 6. Multiply the radius and height of the glass by the scale factor (6) to find the height and radius of the jar.

4) Q17 only has parts a) and b). There's no part c).

Thank you ,,
thats was 0580/21/M/J/10 Q17 C
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_21.pdf
Sorry for misleading

 

[Rockzstar]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w05_qp_2.pdf

question 20 B

 

[Ahmed Al Hilali]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w05_qp_2.pdf

question 20 B

total distance = 100 m
distance from 0 sec to 8 sec = 80.6 m(from (a) )
distance from 8 sec to 10 = 100-80.6=19.4 m
distance = area under graph
19.4 = 1/2 ( Base 1 + base 2 ) x Height were base 2 is the speed when he cross the finish line
so
19.4 = 1/2 ( 12.4 + x ) x 2 >> 19.4 = 12.4 + x >> x = 19.4-12.4=7

 

[Rockzstar]

total distance = 100 m
distance from 0 sec to 8 sec = 80.6 m(from (a) )
distance from 8 sec to 10 = 100-80.6=19.4 m
distance = area under graph
19.4 = 1/2 ( Base 1 + base 2 ) x Height were base 2 is the speed when he cross the finish line
so
19.4 = 1/2 ( 12.4 + x ) x 2 >> 19.4 = 12.4 + x >> x = 19.4-12.4=7

thnxx

 

[notnek01]

Thank you ,,
thats was 0580/21/M/J/10 Q17 C
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_21.pdf
Sorry for misleading

'The angle at the centre is twice the angle at the circumference':

The chord CD subtends angle COD at the centre at angle CED at the circumference so angle CED = 38/2 = 19.

Then angle EDO = 180 - 90 - 19 = 71.

 

[Princess Raven]

GUYS WHATS THE INVERSE for shear and stretch???

 

[notnek01]

GUYS WHATS THE INVERSE for shear and stretch???

Do you mean the inverse of the shear and stretch matrices? Can you explain what you mean?

 

[tweetie]

http://papers.xtremepapers.com/CIE/Cambridge%20IGCSE/Mathematics%20(0580)/0580_s12_qp_23.pdf
q21- pplease someone help asap

 

[Ahmed Al Hilali]

'The angle at the centre is twice the angle at the circumference':

The chord CD subtends angle COD at the centre at angle CED at the circumference so angle CED = 38/2 = 19.

Then angle EDO = 180 - 90 - 19 = 71.

thanks a lot

 

[Princess Raven]

Do you mean the inverse of the shear and stretch matrices? Can you explain what you mean?

yes like for stretch we do 1/k what about shear?

 

[ZaqZainab]

sorry dear but i didnt get anythg :/ i never heard of model nd real...can u tell me which topic is it..ill study nd thnx a lot

lol i took that from the question paper you gve model of a car and the real car dran it

 

[notnek01]

yes like for stretch we do 1/k what about shear?

Can't you just use the same method as you would to find the inverse of any other matrix?

It's really not important to learn the inverse transformation matrices for IGCSE. I'd focus my time on more important areas

 

[notnek01]

Hey there. I have a qs in Oct/Nov 12 qp_23 #17.
I don't understand how to solve it.

Have a look at this thread: https://www.xtremepapers.com/community/threads/im-an-igcse-maths-teacher-post-your-questions-here.24660/page-3

I gave two method for solving this question, one in post #55 and the other in post #79 on the next page.

 

[Rockzstar]

WHaT does plane of Symmetry mean ????

 

[ZaqZainab]

Hey there. I have a qs in Oct/Nov 12 qp_23 #17.
I don't understand how to solve it.

First you find the angle of the sector by using the formula length of the arc=(theta/360)*pie*2*r
which is 4r=(tetaha/360)*pie*2*5r
now moving to the left hand 4r/(Pie*2*5r)=tetha/360 solve this to get thetah= 45.84
now equation for are of sector Area=(thetha/360)*pie*r^2
Area=(45.84/360)*pie*(5r)^2
Are is 10 r^2

 

[ZaqZainab]

WHaT does plane of Symmetry mean ????

when you draw this line the shapes on it sides should look similar Like the letter A has 1 if you ct it from UP to the down the left and right side is same lemme make it little more easier My Face Your face have one line of symmetry if you keep a mirror on the line of symmetry you can see the exact same other side
some things have 2 like the letter H some don't even have one like K an some have infinite like O
#ACOOLTRICK you can use the reflection of your geometry box to see if it is exactly the same that is use your geometry box shine surface a mirror

 

[Jelleh Belleh]

Hi everyone. Quick question, is there any chance mensuration might come in paper 2?

 

[notnek01]

Hi everyone. Quick question, is there any chance mensuration might come in paper 2?

It is rare to see it come up in paper 2 but I see no reason why it won't.

 

[Rockzstar]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_21.pdf

Please Exlain Question 21