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Mathematics: Post your doubts here!

Phoenix Blood

Phoenix Blood

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Umar Ahmed said:
to solve quadratc formulas press for eg in eqn a=2,b=3 &c=5
2then click on shift the Button named RCL and then just press where it is written A press it A value will be set to 2 than do that for all numbers then right the formula like -B+square root(B^2-4AC)/2A first with positive than with negative to check ur answers
Click to expand...
Shear thanxxx! ;) Besides that?
 
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Usman Abdul Jabbar

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Question:

The number of fish on a farmincreases by approximately 10% each month. If there were originally 350 fish, calculate to the nearest 100 how many fish would there be after 12 months ?

(Question from IGCSE Mathematics by Hodder Education 3rd Edition)​

Guys I got an answer with round off of 800 but in the answers it has 1100 please tell me why is it 1100.


Thanks
 
Phoenix Blood

Phoenix Blood

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Usman Abdul Jabbar said:
Question:

The number of fish on a farmincreases by approximately 10% each month. If there were originally 350 fish, calculate to the nearest 100 how many fish would there be after 12 months ?

(Question from IGCSE Mathematics by Hodder Education 3rd Edition)​
Guys I got an answer with round off of 800 but in the answers it has 1100 please tell me why is it 1100.

Thanks
Click to expand...


Compound interest formula: P* (1+(r/100)) ^t

P=350
R=10
T=12
 
eureka!

eureka!

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Phoenix Blood said:
http://onlineexamhelp.com/past-pape...-wise/0580-mathematics-igcse-past-papers-2013

0580_w13_qp_42
Question,5, (d) (ii)
Pl show how to go about... :(
Click to expand...
Asarb.
2/x2 - 1/x2 - 3x = 10 - 3x
Get the -3x on the other side of the equation, so +3x and -3x cancel out each other.
Now, 2/x2 - 1/x = 10
Make both denominators common by multiplying 1/x by x.
Solve 2/x2 - x/x2 = 10:
(2-x)/x2 = 10
Get the x2 on the other side by multiplying it with 10.
Now, 2 - x = 10x2
Make it quadratic:
0 = 10x2 + x - 2

So a=10, b=1, c=-2! :)
 
Phoenix Blood

Phoenix Blood

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Jazakillah :)
eureka! said:
Asarb.
2/x2 - 1/x2 - 3x = 10 - 3x
Get the -3x on the other side of the equation, so +3x and -3x cancel out each other.
Now, 2/x2 - 1/x = 10
Make both denominators common by multiplying 1/x by x.
Solve 2/x2 - x/x2 = 10:
(2-x)/x2 = 10
Get the x2 on the other side by multiplying it with 10.
Now, 2 - x = 10x2
Make it quadratic:
0 = 10x2 + x - 2

So a=10, b=1, c=-2! :)
Click to expand...
 
U

Usman Abdul Jabbar

Messages
65
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98
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Question:

The number of fish on a farmincreases by approximately 10% each month. If there were originally 350 fish, calculate to the nearest 100 how many fish would there be after 12 months ?
(Question from IGCSE Mathematics by Hodder Education 3rd Edition)
Guys I got an answer with round off of 800 but in the answers it has 1100 please tell me why is it 1100.

Thanks
 
U

Usman Abdul Jabbar

Messages
65
Reaction score
98
Points
28
Question:

The number of fish on a farmincreases by approximately 10% each month. If there were originally 350 fish, calculate to the nearest 100 how many fish would there be after 12 months ?
(Question from IGCSE Mathematics by Hodder Education 3rd Edition)​

Guys I got an answer with round off of 800 but in the answers it has 1100 please tell me why is it 1100.

Thanks
 
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