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Q24 is easy and i would like u to try it.didnt understand Q 24 oct/nov 12 paper 23
here is link http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_23.pdf
so here is what to do and if u still dont get then tell
For (a) part the question says ABCD is horizontal and BCQP vertical this tells that any angle between these two will be 90 so by finding one other length find DP by pythagoras
then for (b) part use sin rule to find the angle