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Mathematics: Post your doubts here!

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Q24 is easy and i would like u to try it.
so here is what to do and if u still dont get then tell :D
For (a) part the question says ABCD is horizontal and BCQP vertical this tells that any angle between these two will be 90 :D so by finding one other length find DP by pythagoras :)
then for (b) part use sin rule to find the angle :D
 
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Q24 is easy and i would like u to try it.
so here is what to do and if u still dont get then tell :D
For (a) part the question says ABCD is horizontal and BCQP vertical this tells that any angle between these two will be 90 :D so by finding one other length find DP by pythagoras :)
then for (b) part use sin rule to find the angle :D

did not understand meaning of that any angle between these two will be 90 (oct/nov 12 paper 23 of q24 (a) :cry:
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_23.pdf
 
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did not understand meaning of that any angle between these two will be 90 (oct/nov 12 paper 23 of q24 (a) :cry:
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_23.pdf
look the diagram in ur question is a bit like this. in (b) part the triangle is a bit like this. can u see both the red lines. one line is on the horizontal plane and the other red line is on the vertical plane. meaning on is horizontal and the other is vertical. look in the 2nd pic the angle between vertical and horizontal is 90...
and for the first pic download it and rotate it 180
 

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it like this cube root means to th power of 1/3
so 27^1/ and p^1/3
so we can write 27 as 3^3
so we write 3^3*1/3 ans p^27*1/3
then it becomes 3^1( becuz 3 and 3 get cancelled) and p^9 (becus 27/3 =9)
so answer is 3p^9
thats how u do it
do u understand
 
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it like this cube root means to th power of 1/3
so 27^1/ and p^1/3
so we can write 27 as 3^3
so we write 3^3*1/3 ans p^27*1/3
then it becomes 3^1( becuz 3 and 3 get cancelled) and p^9 (becus 27/3 =9)
so answer is 3p^9
thats how u do it
do u understand
wow. thanks a million! :D:D
 
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