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Mathematics: Post your doubts here!

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I too need help in Transformation ( stretch, shear , single matrix transformation etc )
Dont know anything about these topics /// :(
1) the invariant line : if any point is on this line it doesn't move
2)the scale factor = the distance between image and invariant line / the distance between object and invariant line
here is a video that might help
 
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can someone explain how to find a matrix representing a transformation, pleaaaaaassee
I dont want to memorize them, cause they're they wanna know how did u get it.. so please anyone? :(
here is a simple way to do it but you need to be quick
if u have this one for example Q14
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_22.pdf
put points in matrix this way x
y
so object matrix 1 2 3
1 1 2
the image matrix 3 4 7
1 1 2
by eyes you will find that y didn't change so the lower row will be (0 1)
x has changed notice that x+2y=new x so the upper row will be (1 2)
so 2x2 matrix = 1 2
0 1
the 1 is multiplied by x and 2 by y both added together formed the new x
o by x and 1 by y then only y so new y=y

for other transformation they may stay the same so 1 0
0 1
or the x and y replace each other as (2,1) to (1,2)
so matrix = 0 1
1 0
if they only change sign then matrix = -1 0
0 -1
if they replace each other with other sign matrix = 0 -1
-1 0



hope this helps
i know it may seem complicated but you can try it and if u have any question u can always ask(y)
 
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this is loci
so i'll just tell u how to do it
(a)perpendicular bisector (stand on G by the compus and open it more than the half of the length GH
draw 2 arcs before the line GH and after
do the same when on H but don't change the length opened by the compus
there should be 2 intersections around the line GH join them together to draw the perpendicular bisector )

(b)angle bisector (draw 2 arcs on lines GH and GF when standing on G
Then with the same length stand on the intersection between the arc and the line and draw another arc between the 2 lines repeat it on the other line
draw a line to join the intersection of both arcs drawn in last step and point G)

(c)change 550 to cm
550/100=5.5
open the compus to 5.5 cm then stand on f and draw a circle

R should be nearer to G and line FG and out of the circle
after you answer it send a pic if u r not sure it is right
 
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40 000 -(tax +rent+bills)=12 000
x=bills
40 000-6000-10 800-x=12 000
23 200-x=12 000
-x=12 000-23 200=-11200
x=-11200/-1=11200
bills=$11 200
Ahh Yeah! i forgot the total amount!

Listen same paper, Q5, (e)

to help u save time here is the info of previous parts

angle BAC = 39,.8
angle ABC =115
distance AB= 40 KM
DISTANCE BC = 60 KM

i guess they are askin to find AC?
 
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