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Mathematics: Post your doubts here!

Messages
150
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235
Points
53
Messages
150
Reaction score
235
Points
53
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_41.pdf
question 4 part b and d
question 5 part b ii
question6 part b ii steps

question7 part b iii
question 10 part v

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rida.12.!!
saif mahmoud
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4)b)as AB is parllel to DC
so angle ABD=BDC=40
use sin rule
BC/sin(40)=70/sin(32)
(sin(40)*70)/sin(32)=84.9

4)d)shortest distance means that it is perpendicular to BD so it will make a new right-angle triangle the hyp=55
shortest distance=opp
using sin
sin(40)=opp/55
opp=sin(40)*55=35.4

5)b)ii)
upload_2014-5-11_11-19-0.png

6)b)ii)replace g(x) with x
and x in the equation with y
then make y the subject
then replace the y with g(x)^-1
g(x)=1-2x------->x=1-2y
x-1=-2y
(x-1)/-2=y
(1-x)/2=y
g(x)^-1=(1-x)/2

7)b)iii)median is 50% of maximum number on y-axis the curve reaches(120)
50% 0f 120=(50/100)*120=60
if you noticed he has written the unit seconds means he wants the time which corresponds to cumulative frequency =60
and then lower quarterl = 25%of 120
60% of 120

10)v)sorry can't answer it
 
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