- Messages
- 255
- Reaction score
- 85
- Points
- 38
this one is really easykindly i need help in 2011 21 question 16
The diagram shows a square of side k
The circle inside the square touches all four sides of the square.
A) The shaded area is A cm"2
show that 4a=4k"2-k"3.142"2
3.142 is a value of pie
"2 mean square
Area of whole sq= k2
area of the circle= pie(k/2)sq
so if you take square of k/2 it become k*sq*/4
so
A=k*sq*-pie(k)*sq*/4
multiply every term by 4 so you get rid of denominator
4A=4k*sq*-pie(k)*sq*
i am going to sleep now but you guys better post shit load of questions till morning