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Mathematics: Post your doubts here!

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you guys should get married or something :p no one likes math where i am :p muahaha <oh just the sudden urge to evil laugh, dont mind tht :D >
Y - U - C - K - ! :p You mean i should start looking for math haters while it's the time i have to enjoy? NO FREAKING WAY :D No girl is gonna ruin my life, for now :p
Then i am guessing you live somewhere near the black hole :whistle: You know... math guys got sucked in for having bigger and better brains :p
 
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Y - U - C - K - ! :p You mean i should start looking for math haters while it's the time i have to enjoy? NO FREAKING WAY :D No girl is gonna ruin my life, for now :p
Then i am guessing you live somewhere near the black hole :whistle: You know... math guys got sucked in for having bigger and better brains :p
BAHAHA sucked in for having bigger and better brains? :ROFLMAO: it's a possibility , tonna competition so they thought why not get rid of it :p
 
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you guys should get married or something :p no one likes math where i am :p muahaha <oh just the sudden urge to evil laugh, dont mind tht :D >

FailTest3.jpg
 
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Can anyone teach me full and detail way on finding the nth term, I always got confused with it

Learn these 2 formulas:

1) This formula can only be applied if the difference is constant between the first and the second, second and third etc.
nth term = a + d (n - 1)
where:
'a' is the FIRST term
'd' is the DIFFERENCE between the terms

2) This formula can only be applied if, in simple terms, the first term is multiplied by a number to get the second term... and the second term is multiplied by the same number to get the third and so on:
nth term = ar^(n-1)
'a' is the FIRST term
'r' is the number they are being multiplied with

There are many questions you can't solve even when you know these sequences. For that, you need to use some common sense and the sequences already give ;)
 
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Untitled1.pngprob3.pngprob2.pngprob.pngprob3.png
ive got a couple of questions so plzzzz people help me out!!
ok first one ) can someone plz explain for me how to do this briefly?
View attachment 8472
the second one is in a) they ask for the area then in letter b) they mention that the answer in a) was the circumference ???? so what am i supposed to find ?
View attachment 8473
after calculating the distance=area undergraph which is 130 m what should i do?? to find the max speed ??
i tried doing the speed = distance/time which is 130/16 = 8.125 but that wasnt the right answer
View attachment 8474
now the last one im stuck on b)
View attachment 8475
THANK U in advance to whoever helps me in this :D
 
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isnt that the inverse?
In inverse first we have to multiply the correspond values then that answer we have to divide with 1 it’s inverse rule then change the sign and position how I have done
· (2*3)-(4*1)
· 6-4=2
· ½ (3 -1)
· (-4 2)
· Then multiply ½ with 3,-1,-4 and 2
· Hope u got it thank you :)
 
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i Did not Get the Question 8 part b!!
Put your ruler on the Y axis and get the value 0.5 from the graph then move your ruler vertically on X axis between the two curves till touch the two curves by the value 0.5 in two points, "this represent the difference between the two curves" , then get the value from X axis around 66
(it is same as part ( a) however the two points at same point the entersict because the value was zero)
 
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ive got a couple of questions so plzzzz people help me out!!
ok first one ) can someone plz explain for me how to do this briefly?
View attachment 8472
the second one is in a) they ask for the area then in letter b) they mention that the answer in a) was the circumference ???? so what am i supposed to find ?
View attachment 8473
after calculating the distance=area undergraph which is 130 m what should i do?? to find the max speed ??
i tried doing the speed = distance/time which is 130/16 = 8.125 but that wasnt the right answer
View attachment 8474
now the last one im stuck on b)
View attachment 8475
THANK U in advance to whoever helps me in this :D
from where u got these question
 
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A rectangular photograph measures 23.3 cm by 19.7 cm, each correct to 1 decimal place.
Calculate the lower bound for
the perimeter and the area.
lower bound for area =23.25*19.65
lower bound for perimeter=2(23.25+19.65)

about the question 12
edc=180 - 109 (angles between parallel lines add up to 180)
=71
FAB= ABC
sum of internal angles = 720
angle EDC = 109( parallel lines)
let fab = abc= x

2x+95+109+71+109=720
2x=720-384
x=168
 
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A rectangular photograph measures 23.3 cm by 19.7 cm, each correct to 1 decimal place.
Calculate the lower bound for
the perimeter and the area.

A = 23.3 B =19.7
Correct to 1 decimal Lower bound A1 = 23.3 -0.05 = 23.25 B1 = 19.7-0.05= 19.65

Lower bound for the permeter = 2 * A1 + 2 * B1 = 2 * 23.25 + 2 * 19.65 = 2 * 42 = 85.8 cm

Lower bound for the area = A1 * B1 = 23.25 * 19.65 = 456.8625 = 456.9 cm
 
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