Mathematics: Post your doubts here!

[bluefa1con]

Search function?

you can search on xtreme papers -_-

 

[Hamzeh S]

you draw a mirrored curve and the answer is at the given value of x

he didnt give me a value of x he asked for a value of x when f-1(x) = 1.7

 

[InternationationalGuy]

right, do you know about LSF and VSF? its a long story, but
(length/length)^3 = volume/volume
in the question it says mass, which is proportional to volume

so (2/6)^3 = 4/x
there you go.

Thank you. I'll ask you other stuff i dont know later. Thanks again.

 

[sma786]

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use the formula a+(n-1)d ((( but only with artjematic seq. { adding or subtracting } )))
a= first term
d= common difference
s0 it will be --> 2n-1 then put the root
then for b) (2 x 29)-1 = 57 = root 57
hope i helped ...check it if it is ok

Thanks alot !!

 

[sma786]

if some1 reply so plz do tell me kindly thank you

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use the formula a+(n-1)d ((( but only with artjematic seq. { adding or subtracting } )))
a= first term
d= common difference
s0 it will be --> 2n-1 then put the root
then for b) (2 x 29)-1 = 57 = root 57
hope i helped ...check it if it is ok

Asnwer given by always-smile =)

 

[sma786]

http://www.xtremepapers.com/CIE/ind...E/0580 - Mathematics/&file=0580_w10_qp_22.pdf ..

Question 7 .. HELP PLEASE !!

 

[PhyZac]

http://www.xtremepapers.com/CIE/index.php?dir=Cambridge IGCSE/0580 - Mathematics/&file=0580_w10_qp_22.pdf ..

Question 7 .. HELP PLEASE !!

a+tb = a+(3t-5)b
a+tb= a+ 3tb - 5b
a - a + 5b = 3tb - tb
5b = 2tb
5 = 2t ( by canceling the b )
t= 5/2 = 2.5

 

[Hamzeh S]

Put your ruler on the Y axis and get the value 0.5 from the graph then move your ruler vertically on X axis between the two curves till touch the two curves by the value 0.5 in two points, "this represent the difference between the two curves" , then get the value from X axis around 66
(it is same as part ( a) however the two points at same point the entersict because the value was zero)

but 23-27 can also work :S ?

 

[bluefa1con]

he didnt give me a value of x he asked for a value of x when f-1(x) = 1.7

i havnt solved that question yet but it should be like the value of x of graph of f-1 where y=1.5

 

[FrostFlash]

sum1 help me wid oct/nov 2005 q 7 b

 

[Maz]

sum1 help me wid oct/nov 2005 q 7 b

It was answered a while back on page 69.

 

[GetSomeLife]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

 

[Maz]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

Umm... there isn't any q.24 (d.ii) here. did you mean (b.ii)​

​

 

[bluefa1con]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

(0 -1)
(1 0)


btw what is that subject code for ?

 

[Rrrrony]

Can we use the formula of Compound interest in our exam? Im saying this because i heard that it's not the right thing to do. The formula im talking about is p=(1+r/100)^n . Please do tell me if anyone of u is really sure about it. Thanks in advance

 

[sma786]

a+tb = a+(3t-5)b
a+tb= a+ 3tb - 5b
a - a + 5b = 3tb - tb
5b = 2tb
5 = 2t ( by canceling the b )
t= 5/2 = 2.5

hey thanks alot !!

 

[sma786]

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_w10_qp_22.pdf

Question 18, anybody can solve ?!?!

 

[Warrior66]

could someone answer this question for me?:.........
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_2.pdf
Q no. 21b.
Please asap!!! :S

 

[bluefa1con]

Can we use the formula of Compound interest in our exam? Im saying this because i heard that it's not the right thing to do. The formula im talking about is p=(1+r/100)^n . Please do tell me if anyone of u is really sure about it. Thanks in advance

yes u do use that formula in exam

 

[Maz]

could someone answer this question for me?:.........
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_2.pdf
Q no. 21b.
Please asap!!! :S

You have 2 line equations. So, you use them and solve as simultaneous equations.
2x + 3y = 17
4x - y = 6

4x + 6y = 34
-4x + y = -6 (change the signs)
(eliminate 4x and -4x and add the remaining)

7y = 28
y=28/7
y= 4
(use it in either of the equations)
4x-(4)=6
x=(6+4)/4
x=2.5

Thus the coordinates are (2.5, 4)