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Mathematics: Post your doubts here!

sma786

sma786

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A rod has length 2.9 m, correct to 1 decimal place.
What is the upper bound for the length of the rod?
 
sma786

sma786

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Muzammil100 said:
Can anybody help me in this question

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_41.pdf

Q 6 ) From b) onwards

Obtuse is more than 90 so................
Click to expand...

Sin 26/79 = Sinx/135 .. cross multiply we get 0.74911 etc, Sin inverse this, we get 48.51 .. its askng the obtuse value, so 48.51 - 360 = 131.5 ... there u go ;) hope i helped

then in part c, 131.5+26-180 = 22.5 .. so , Sin90/79 = Sin22.5/x .. cross multiply u get 30.23 .. there u go again :)

then in part d, area of the big trianglle, is 0.5*95*120*sin77 .. u get 5554/180 = 30.85 .. a houses cannot b in decimals :p so its 30 :)
 
Muzammil100

Muzammil100

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sma786 said:
Sin 26/79 = Sinx/135 .. cross multiply we get 0.74911 etc, Sin inverse this, we get 48.51 .. its askng the obtuse value, so 48.51 - 360 = 131.5 ... there u go ;) hope i helped

then in part c, 131.5+26-180 = 22.5 .. so , Sin90/79 = Sin22.5/x .. cross multiply u get 30.23 .. there u go again :)

then in part d, area of the big trianglle, is 0.5*95*120*sin77 .. u get 5554/180 = 30.85 .. a houses cannot b in decimals :p so its 30 :)
Click to expand...

Thanks but
"48.51 - 360 = 131.5"
 
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