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Mathematics: Post your doubts here!
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
inverse matrix is easy !!
1) find the determinant
2)then put the determinant 1/IAI with matrix !!
inverse matrix is easy !!
1) find the determinant
2)then put the determinant 1/IAI with matrix !!
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
How to solve inequalities
How to solve inequalities
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
wat type of inequalities...???
wat type of inequalities...???
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
how to solve inequalities sums............................
PLZ help
how to solve inequalities sums............................
PLZ help
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
you mean this ???
2x+4>5x-8
??
you mean this ???
2x+4>5x-8
??
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
IGCSE MATH 0581 PAPER 4 NOVEMBER 2005 QUESTION 5 PART C
ANY HELP WOULD BE APPRECIATED
IGCSE MATH 0581 PAPER 4 NOVEMBER 2005 QUESTION 5 PART C
ANY HELP WOULD BE APPRECIATED
XPFMember
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Assalamoalaikum!!
well...i saw that question ..it's easy....but i can only tell u that in specific if u can show me the solution....otherwise i wont be able to explain it..or just let me know how it is...like what's it max./min. point
Assalamoalaikum!!
well...i saw that question ..it's easy....but i can only tell u that in specific if u can show me the solution....otherwise i wont be able to explain it..or just let me know how it is...like what's it max./min. point
XPFMember
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
well i'm not checking this...as your query has been answered here
by the way sorry for the late reply!
Assalamoalaikum!!boodi196 said:Can u help me in physics about KE?
MJ 2009 paper 3 physics question 5 section Bi) PLEASE HELP ME
well i'm not checking this...as your query has been answered here
by the way sorry for the late reply!
XPFMember
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Check if this helps
Assalamoalaikum!!MohammedNoor said:
Check if this helps
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nice Question !! is it from Past papers ?? It sets right ??
nice Question !! is it from Past papers ?? It sets right ??
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
i think that the answer is 20
u can solve this question by drawing a venn diagram
Here is the solution:-
11+12+6+7+3x=60
therefore x=8
nowww.....
add 8+6+6=20
Therefore pills containing Vitamin A=20
i think that the answer is 20
u can solve this question by drawing a venn diagram
Here is the solution:-
11+12+6+7+3x=60
therefore x=8
nowww.....
add 8+6+6=20
Therefore pills containing Vitamin A=20
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
@HyDraZin3= You missed the pills that contain only Vitamin A. And you have to add 8 twice and not 6 twice. So 8+8+6+12=34..
The total number of pills containing Vitamin A are 34.
You should use venn diagram for this question. It'll make it very simple.
@HyDraZin3= You missed the pills that contain only Vitamin A. And you have to add 8 twice and not 6 twice. So 8+8+6+12=34..
The total number of pills containing Vitamin A are 34.
You should use venn diagram for this question. It'll make it very simple.
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Exactly @hamidali391 !
Exactly @hamidali391 !
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
No problem any more questions just ask !!
No problem any more questions just ask !!
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
assalamualaikum math angel.....
I just wanted to ask is there any specimen paper for year 2011 IGCSE extended maths..if so plz give me the link...
Thanx...
assalamualaikum math angel.....
I just wanted to ask is there any specimen paper for year 2011 IGCSE extended maths..if so plz give me the link...
Thanx...
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Go through Extended maths at XP and look for Sp abbrevation which is for specimen paper and then download the 2011 one !!
Go through Extended maths at XP and look for Sp abbrevation which is for specimen paper and then download the 2011 one !!
XPFMember
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Waalaikumassalam!!
No, specimen papers are published when they change the pattern/style of the questions. I just checked the CIE Website, the latest specimen paper published was the Paper 4 in the year 2009 !
Check the link above to access the latest specimen paper.
Hope this helps!
Thanks for your query, Jazak Allah Khair!
Please do not hesitate if you have any more questions!
Farhana.Crystalaire said:
Waalaikumassalam!!
No, specimen papers are published when they change the pattern/style of the questions. I just checked the CIE Website, the latest specimen paper published was the Paper 4 in the year 2009 !
Check the link above to access the latest specimen paper.
Hope this helps!
Thanks for your query, Jazak Allah Khair!
Please do not hesitate if you have any more questions!
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
Please help.
Question:
f:x -> (x+2)/a; a not 0. g:x -> 2x^2+1. If gf(x) = 2x^2 - bx +9, find the values of a and b.
The answer is a=1, b= -8 and a= -1, b= -8
So here is what I worked out so far:
gf(x) = 2 ( (x+2)/a )^2 + 1 = 2x^2 - bx + 9
therefore 2 ( (x+2)/a )^2 = 2x^2 - bx + 9 - 1
so then 2 ( (x+2)/a )^2 = 2x^2 - bx + 8
but how do i solve for a and b when there is only 1equation to work with?
Please help.
Question:
f:x -> (x+2)/a; a not 0. g:x -> 2x^2+1. If gf(x) = 2x^2 - bx +9, find the values of a and b.
The answer is a=1, b= -8 and a= -1, b= -8
So here is what I worked out so far:
gf(x) = 2 ( (x+2)/a )^2 + 1 = 2x^2 - bx + 9
therefore 2 ( (x+2)/a )^2 = 2x^2 - bx + 9 - 1
so then 2 ( (x+2)/a )^2 = 2x^2 - bx + 8
but how do i solve for a and b when there is only 1equation to work with?