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Mathematics: Post your doubts here!

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May someone please explain to me how to get the coordinates of the point of intersection of the straight lines.....
2x+3y=11
3x-5y=-12
I have my paper 2 tomorrow:\
 

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jamescc said:
May someone please explain to me how to get the coordinates of the point of intersection of the straight lines.....
2x+3y=11
3x-5y=-12
I have my paper 2 tomorrow:\

Try to imagine what is the point of intersection?! See it's the point where both the line meet..which means the coordinates of that point are ofcourse same for both lines...that is x and y values are same in the eqn of both the lines!

Therefore, when you solve the 2 eqns simultaneously, it'll give u the x and y values for the point of intersection!

In short, solve the two eqns simultaneously...and dont forget to write in the form (x , y)
 
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i need the workings to get the answers of these questions. any help appreciated... plx plx plx help me 2day test!!
 

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1)Remember it is the constant maximum speed.. In the graph constant speed is b/w 2 and 10 therefore 10-2 = 8
The next hint is see the y-axis and x-axis.Y axis is speed metre/second .. X-axis is time minutes so we will had to definitely convert the minutes into second to make same units. So, multiply 8 x 60 = 480seconds


2)1/2 x 2 x 15 ---> Remember we should convert into seconds 2 x 60 = 120 1/2 x 120 x 15 = 900m
8 x 15 -----> Remember we should convert into seconds 8 x 60 = 480 480 x 15 = 7200m
1/2 x 4 x 15 ----> Remember we should convert into seconds 4 x 60 = 240 1/2 x 240 x 15 = 1800 m
TOTAL DISTANCE = 900 + 7200 + 1800 = 9900 metres


3)Acceleration = Speed / Time
= 15 / (2 x 60)
= 15/120 = 0.125 m/s ^2


*****************************************BEST OF LUCK FOR TODAY'S PAPER 21***************************** :good: :good: :good: :good: :good:
 
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I have a question haha:

A spherical balloon of radius 3 metres has a volume of 36π cubic metres.
It is further inflated until its radius is 12 m.
Calculate its new volume, leaving your answer in terms of π.

The answer is 2304π but I have no clue how they got the answer.

Thanks in advance.
 
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xXRUSHXx said:
I have a question haha:

A spherical balloon of radius 3 metres has a volume of 36π cubic metres.
It is further inflated until its radius is 12 m.
Calculate its new volume, leaving your answer in terms of π.

The answer is 2304π but I have no clue how they got the answer.

Thanks in advance.
 

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Salam......Guys how do we find the matrix which represent different kinds of transformation,.......plzz help!!
 
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hamza96 said:
Salam......Guys how do we find the matrix which represent different kinds of transformation,.......plzz help!!
You learn the main ones which are in the syllabus. You can find them at the end of this booklet.
 

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thannxxxx............and any tips of solving the last question of paper 4 which usually is the nth term or seqence one.....it usuall coms of 10 or 12 marks!!!
 
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Please help me do question 11c in Maths Extended Paper 0580/43/O/N/10 (paper4 variant 3 winter oct/nov 2010)

Please explain and show me the methods. Thank you!!!!!!!!!
 
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orimairu said:
Please help me do question 11c in Maths Extended Paper 0580/43/O/N/10 (paper4 variant 3 winter oct/nov 2010)

Please explain and show me the methods. Thank you!!!!!!!!!
can u send the link ............. frm net???
 
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i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.
 
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hamza96 said:
http://www.xtremepapers.com/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_s10_qp_41.pdf .............guys Q.6.....how do find mean.........tell how to solve these typa questionssss nd thanxx
60 potatoes

MASS Mid-point(x) Frequency FX
10-20 15 10 150
20-40 30 30 900
40-50 45 20 900

Therefore Mean = Sum of FX / Sum of frequency
Sum of FX= 1950
Sum of F = 60
There fore mean = 1950/60 = 32.5g
 
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sspigcse said:
i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.
AoA!
For help on transformation matrices, please check my previous post here.
The formula to find the nth term of a quadratic sequence is: a + (n - 1)d1 + 1/2 (n - 1)(n - 2)d2 ,
where: a is the 1st term of the sequence
d1 is the difference b/w the first two terms of the sequence
d2 is the constant difference b/w any two terms of the derived sequence.
 
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I have some doubts on q 5 e) , 6 a) iii) and 10 c)ii) on paper 4 november 2008. I appreciate if anyone can explain this because i have my test on monday. Thank you.
 
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