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whole Q11 or just some parts?Can someone please help me with Q11 from 0580, June 2013, Paper 42? I'd like to see your working as well...
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whole Q11 or just some parts?Can someone please help me with Q11 from 0580, June 2013, Paper 42? I'd like to see your working as well...
whole Q11 or just some parts?![]()
The whole question please...
Yes I would appreciate that!sorry for late reply and not answering. hope ur test went well. and if u still want solutions for these lemme know![]()
for the first paper, if u could do (a) for Q10 then (b) part is nothing. u found n in (a) part. now use that to find dots of the different numbers and add up.Yes I would appreciate that!![]()
and for the second paper i think u need to make two simultaneous equations. so first put n=3. Thus the Right Hand Side (RHS) will be equal to 14. u'll get an equation of a and b. then put n=4 and this time the RHS will be equal to 30. u'll get another equation in terms of a and b. solve both simultaneously and u'll get the valuesYes I would appreciate that!![]()
Are we supposed to use the cubic sequence formula? an^3+bn^2+cn+dand for the second paper i think u need to make two simultaneous equations. so first put n=3. Thus the Right Hand Side (RHS) will be equal to 14. u'll get an equation of a and b. then put n=4 and this time the RHS will be equal to 30. u'll get another equation in terms of a and b. solve both simultaneously and u'll get the values
any problem lemme know![]()
and for the last part, in one complete circle its 360 degrees. and in similar triangles the corresponding angles remain the same. thus 360 is divided by the angle we calculated in d(i) i.e. 18.4
I get n=19 but marking scheme says its n=20and for the last part, in one complete circle its 360 degrees. and in similar triangles the corresponding angles remain the same. thus 360 is divided by the angle we calculated in d(i) i.e. 18.4
its 19..something i think.I get n=19 but marking scheme says its n=20
I need help in sequences please..!
A sequence is given : 4,12,24,40..... find the nth term
Is there any specific way of doing it? Any help will be appreciated.
But i believe that the above sequence is neither arithmetic nor geometrical... so the formulas cannot be applied :/this is from the maths formula booklet for A levels
hopefully it will help u.
its a quadratic sequence . quadratic sequence is when the common difference comes to the second level.But i believe that the above sequence is neither arithmetic nor geometrical... so the formulas cannot be applied :/
Nice.. Thanks alot..!its a quadratic sequence . quadratic sequence is when the common difference comes to the second level.
ive uploaded some images showing the working . hope it helps.![]()
ur welcome, its ok even i hate sequences.... yes u can use the same method . btw are these from past papers?Nice.. Thanks alot..!
What type of a sequence is this one : 3,6,7,-2? Can i use the same formula here aswell? .... Sorry if i seem annoying...Sequences are my weak point
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