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Mathematics: Post your doubts here!

Nibz

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Nibz

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http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_42.pdf

q7 (ii) , why have they taken time as 15 and s as 225? shudnt it be 0 and s=0 like the previous question? because it says total distance travelled after 15s and 225m is fr the first equation.

Once im clear with this , Im done with mechanics :D Tnx
No, you can't take time as 0. That would make the distance 'infinity' and not 'zero'. To put it simple, you can't put zero in the denominator. That is the reason it's clearly mentioned in the question that at t= 15, s= 225
Put these values in the equation, and you will get the value of Constant. :)
 
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No, you can't take time as 0. That would make the distance 'infinity' and not 'zero'. To put it simple, you can't put zero in the denominator. That is the reason it's clearly mentioned in the question that at t= 15, s= 225
Put these values in the equation, and you will get the value of Constant. :)
But in the previous question , y cudnt we take t as 0.5? instead we took t=0 . And also the distance we found is fr the first equation
 
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cant solve Q:1, 3 ,4 P42 oct/nov/09 Q:3 , 5 and 7 Oct/Nov/2010 P42 plzzzzzzzzzz help . . .. . . . .plzzzzzzzzzz :( :cry:
 

Nibz

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But in the previous question , y cudnt we take t as 0.5? instead we took t=0 . And also the distance we found is fr the first equation
t= 0.5? I don't know which question are you talking about.
And no, these conditions are for all the three parts (i) (ii) and (iii).
 
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t= 0.5? I don't know which question are you talking about.
And no, these conditions are for all the three parts (i) (ii) and (iii).
I mean in first part the time taken was 0.5 so dont we take t as 0.5 in 2nd question? like we did fr the other paper u jst answered
 
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can any one pls give me the formulas for finding workdone against resistnce of friction, with respect to kinetic, potential energy??
plss!! :( :'(
 
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