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Yes, im 100% sure.r u sure? Im pretty confused? So we find the constants twice in 2 integration?
Yes, we do that, but indefinite integration does not come for 2 times integrating!
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Yes, im 100% sure.r u sure? Im pretty confused? So we find the constants twice in 2 integration?
It's the horizontal component of the Tension 'T' in the string.i have a mechanics question ( M1) may june 2006question 5, the first part. from where did the mark scheme get the cos 45 from? :S:S:S
wts that? indefinite integration? When we take limits?Yes, im 100% sure.
Yes, we do that, but indefinite integration does not come for 2 times integrating!
Q 7(ii) , they havent found the constan in second integration :Yes, im 100% sure.
Yes, we do that, but indefinite integration does not come for 2 times integrating!
It's because when you take limits, there is no constant involved. And 2.5 and0 are our limits in 7(ii) integration.Q 7(ii) , they havent found the constan in second integration :
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_4.pdf
ms:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_ms_4.pdf
Indefinite is when we do not take limits like the one i just did for you.wts that? indefinite integration? When we take limits?
It's because when you take limits, there is no constant involved. And 2.5 and0 are our limits in 7(ii) integration.
Ok its clear now tnxIndefinite is when we do not take limits like the one i just did for you.
Definite is the one in which we take limits
No, you can't take time as 0. That would make the distance 'infinity' and not 'zero'. To put it simple, you can't put zero in the denominator. That is the reason it's clearly mentioned in the question that at t= 15, s= 225http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_42.pdf
q7 (ii) , why have they taken time as 15 and s as 225? shudnt it be 0 and s=0 like the previous question? because it says total distance travelled after 15s and 225m is fr the first equation.
Once im clear with this , Im done with mechanics Tnx
But in the previous question , y cudnt we take t as 0.5? instead we took t=0 . And also the distance we found is fr the first equationNo, you can't take time as 0. That would make the distance 'infinity' and not 'zero'. To put it simple, you can't put zero in the denominator. That is the reason it's clearly mentioned in the question that at t= 15, s= 225
Put these values in the equation, and you will get the value of Constant.
t= 0.5? I don't know which question are you talking about.But in the previous question , y cudnt we take t as 0.5? instead we took t=0 . And also the distance we found is fr the first equation
Mind posting the links?cant solve Q:1, 3 ,4 P42 oct/nov/09 Q:3 , 5 and 7 Oct/Nov/2010 P42 plzzzzzzzzzz help . . .. . . . .plzzzzzzzzzz
http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_w08_qp_4.pdft= 0.5? I don't know which question are you talking about.
And no, these conditions are for all the three parts (i) (ii) and (iii).
I mean in first part the time taken was 0.5 so dont we take t as 0.5 in 2nd question? like we did fr the other paper u jst answeredt= 0.5? I don't know which question are you talking about.
And no, these conditions are for all the three parts (i) (ii) and (iii).
posts links of Mark scheme and question papers plz it wil be gr8[/quote
Its okay... I got the answer.... thanx anyway... some careless mistake..
Mind posting the links?
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