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Also with http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_31.pdf
q8 part ii and iii
q8 part ii and iii
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I cant understand . Can u give me the solution ?How to get the initial value for q4 ?
why is it "360-50.7"
I dont undestand this part
"in 2nd quadrant, only sin is +ve
then, do 360-190.4=169.6
then, 180-169.6=10.4"
Oh I did that question in the morning..http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s03_qp_3.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s03_ms_1 2 3 4 5 6 7.pdf
Q2(ii) . the integral of cotx is ln sinx . but after substituting the limits how can we get the answer stated ?
oh ! thanks a lot !Oh I did that question in the morning..
View attachment 9658
thanks for your help I finally undestand it!cos is only +ve in the 4th quadrant, meaning it is -ve in quadrant 2 and 3
cos 169.6 gives u -0.9835....u have to get a +ve value for X... u could just do 180-169.6.
cos 10.4 is +ve...m not sure if this is clear.
anytime =]oh ! thanks a lot !
you mean the uv method? ...Hey can sum 1 tl me tat Formula wen we integrate and we Cant use ln because the power of x in the denominator
is Not linear? The 1 tat goes like 1/a and tan sumthing?
plx tel asap have ppr tommz!
show me a question.. cause I can't think of any such integration. -_- In fact, check the syllabus and then ask againPlx help sum1!
I'm in a rush so I won't do it unless you really need help but substitude e^2x with yhttp://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
how to differentiate no.2? I know its using division differentiation but can anyone show me? thank you.
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