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Mathematics: Post your doubts here!

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you integrate the equation with limits 1 and 0 to give you the area of the first region(R1), then you do it again with limits 2 and 1 this being the region (R2)
you'll have the same answers (1/4) so you can say R1=R2
you integrate the equation with limits 1 and 0 to give you the area of the first region(R1), then you do it again with limits 2 and 1 this being the region (R2)
you'll have the same answers (1/4) so you can say R1=R2
you integrate the equation with limits 1 and 0 to give you the area of the first region(R1), then you do it again with limits 2 and 1 this being the region (R2)
you'll have the same answers (1/4) so you can say R1=R2
thanks (Y)
 
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umm putting it simply find the angles that the tangent makes with the x-axis, subtract the larger from the smaller and voila you have the acute angle

basically you differentiate the curve equation and first put in the x- coordinate of p then of q
what you'll have is (since the gradient y/x)
tan(theta)=the first gradient(2/3)
tan(alpha)= second(3/4)
larger angle(56.3) - samller angle(36.9)
answer (19.4)

the brackets are the answers..
 
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Differentiate the equation of the curve. you would get dy/dx i.e equation of then gradient of curve.
put the x-co-ordinates of P and Q in the gradient equation. You would get gradient of tangent at P and Q.
let the gradient of tangent at P= m1
let the gradient of tangent at Q=m2
Use formula to find angle
tan(x) = m1 - m2 / (1 + m1m2)
find x in degrees.
 
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General Questions:
Should we underline our final answers with a double line? Some people say we should because it helps the examiner.

And when writing down degrees in radians... do we have to use the word 'radian' ? such as 1.21 radian
 
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i dont suggest it as some times it might make your answer messy and unreadable . ( if u have messy writting :p)
 
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well in 6i) cos(x/2 + pie/6) =1
cos-1(1)=x/2 +pie/6
0=x\2 +pie/6
pie/3 =x
6ii f(g)= 1 hence sub
cosx/2 +pie/6 =1
cosx/2 =1-pie/6
cosx= 0.4764*2
cosx=0. 9528
x=0.31 and for the negative value we have to take x= -0.31
x=+-0.31
 
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