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Till Q 5 it was perfect Alhamdulillah! messed up a bit in Q6 ii) thou. :/How was mechanics, you guys ? Mine was good Alhamdulillah...
No discussion of the questions allowed though
ummm okay
/d(x)=3a sin^2t cost/-3a sint cos^2t )
ummm okay
here's part 1 )
dy/d(t)=3asin^2t(cost)
d(x)/d(t)=-3a sint cos^2t
d
dy/d(x)=-tant
now for part 2 (the tricky bit
.gradient=-tant , x=acos^3t, y=asin^3t
y-asin^3t= -tant(x-acos^3T)
y-asin^3t=-(sint/cost)x+(sint/cost)acos^3t
ycost-asin^3tcost=-xsint+asintcos^3t
xsint +ycost=asintcost(cos^2t+sin^2t)
xsint+ycost= asintcost
and part 3
for y-intercept put y=0,
xsint+o= asintcost
x=acost
for y-intercept put x=0
0+ycost=asintcost
y=asint
coordinates of x are (acost,0)
coordinate of y are (0, asint)
lenght=((acost)^2+(asint)^2)^1/2
=(a^2cost^2+a^2sint^2)^1/2
=(a^2(cos^2t+sin^2t))^1/2
=(a^2)^1/2
=a
you get it ?
umm i substituted my values in (y-y1)=m(x-x1) where y1 and x1 are the co-ordinates
thank you can u please ues thatumm i substituted my values in (y-y1)=m(x-x1) where y1 and x1 are the co-ordinates
if you want it in the y=mx + c format i guess you could do it
if you don't get it .........then i will try it with y=mx+c and do it for you
(i)
I had same doubt, but apparently the reason is, it is less than or equal to the specific value. When it is only less than then only 50 not 50.5
here
wats the question??
two fair dice are thrown simultaneously. The random variable H is the highest common factor of the two scores. Tabulate the probability distribution of H, combining together all the possible ways of obtaining the same value
look i cant very well make the table here but u must have done these questions somewhere where u have a table.... its mostly in the dice questions.. u have numbers for one die in the top row and for the other in the first column and u give the results in all the 36 boxes that come from the 6 rows and 6 columns .
look at the table... fill in the solution boxes urself
for 1 and 1 the HCF will be 1 so u write one, for 4 and 2 it will be 2 and so on... if u don't get it then get back to me but i think this is pretty much how u're supposed to do it. and tag me in any stats question uu hav becaus it'll help me prepare too
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