Mathematics: Post your doubts here!

[Gordious]

1/(2x-1)(x-1) . Find the bionomial expression upto x^3 and find the range of values of x for this expression is valid.
For range, the ans is -0.5<x<0.5, how?

 

[VinnCh]

Is it something like this? Then i tend to infinity and obtain P = 100/e

View attachment 26639
THANK YOU SO MUCH!! Remembered in my prayers!

Yes, you are right! I am glad that you understood the question. =)

 

[abbey789]

Given that y = 0 when x = 1, solve the differential equation
xydy =y2 +4, dx
obtaining an expression for y2 in terms of x.
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf
Question 5. PLEASE!

 

[Soldier313]

Aoa wr wb
Can someone please give me a detailed explanation for qn 10 ii of this paper, how do they get the vector parallel to the plane, but not parallel to line l
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_3.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_ms_3.pdf


Thank you .

And qn 10 ii of this paper please

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_31.pdf

littlecloud11 PhyZac Esme and everyone else doing p3

 

[farhan143]

Can some one give me a detailed explanation for the follwing question
2012 - MJ - 9709 - Statistics - AS - p61-

 

[SonalDhanturi]

13 sin(2x + 67.38) = 11
Now solve it

I tried that, i got x= -9.6 (1dp). Thats apparently the wrong answer

 

[Silent Hunter]

How to do further than this : -ln 4 - ln 2 .... wil it be ln (4/2) ..... the blue minus is confusing me ?

any one?

Rutzaba
Esme

anyone ? thanks alot

 

[iKhaled]

How to do further than this : -ln 4 - ln 2 .... wil it be ln (4/2) ..... the blue minus is confusing me ?

any one?

Rutzaba
Esme

anyone ? thanks alot

-ln4-ln2 = -(ln4+ln2) = -ln(4x2) = -ln8

 

[Esme]

How to do further than this : -ln 4 - ln 2 .... wil it be ln (4/2) ..... the blue minus is confusing me ?

any one?

Rutzaba
Esme

anyone ? thanks alot

It'll be ln( 1/(4x2) )

 

[Silent Hunter]

It'll be ln( 1/(4x2) )

with a positive sign ?

 

[TaffsAsLevel]

It's better you show all the steps for whichever method you choose. Because with vectors there's always more than one way to obtain answer. You can do whatever way seems easy or short to you but show how you've done it.

it's actually june 2010 paper 32 qp 9. (ii) 6 marks where they ask find the length of AB, given the line equation that meet the plane p at A and plane q at B so that AB direction vector would just be the direction vector given in the line eq. so instead I just find |AB| magnitude and got the correct answer, that's very short and I got 3 which is correct in markscheme. So should I explain it in words then?

 

[Esme]

with a positive sign ?

Yep. The answer on your calculator will automatically be negative. It's like writing :
ln1 - ln4 - ln2 which is the same as 0-ln4-ln2= -ln4-ln2

 

[Esme]

And qn 10 ii of this paper please

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_31.pdf

littlecloud11 PhyZac Esme and everyone else doing p3

Okay hold on...lemme have a look at the question.. Vectors is my least favourite topic, so I usually skip explaining those questions.

 

[Soldier313]

Aoa wr wb'
Could someone please urgently post some good short notes on vectors??
JazakAllah khair!

 

[Esme]

it's actually june 2010 paper 32 qp 9. (ii) 6 marks where they ask find the length of AB, given the line equation that meet the plane p at A and plane q at B so that AB direction vector would just be the direction vector given in the line eq. so instead I just find |AB| magnitude and got the correct answer, that's very short and I got 3 which is correct in markscheme. So should I explain it in words then?

I don't think you should have to... but I can't be certain

 

[Soldier313]

Okay hold on...lemme have a look at the question.. Vectors is my least favourite topic, so I usually skip explaining those questions.

Thanx a ton sis!

 

[Esme]

Aoa wr wb'
Could someone please urgently post some good short notes on vectors??
JazakAllah khair!

Wa laikum as salaam
Might be of help

 

[littlecloud11]

And qn 10 ii of this paper please

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_31.pdf

littlecloud11 PhyZac and everyone else doing p3

For the summer 05
10ii) You know that one of the points on line l is 4i -2j +2k
Let this point be X.
Find the direction vector of AX
AX =(4 -2 2) -(2 2 1) =(2 -4 1)
As both A and X lie on the plane the normal of the plane is also normal to this direction vector.
You already know the direction vector of line l.
find the cross product of these two direction vectors to find the normal of the plane.
(2 -4 1) x (1 2 1)
=-6i -j +8k
Now,
r.n = a.n
(x y z). (-6 -1 8) = (-6 -1 8) (2 2 1)
-6x -y +8z =-6
or
6x + y -8z =6

 

[Esme]

And qn 10 ii of this paper please

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_31.pdf

littlecloud11 PhyZac Esme and everyone else doing p3

Equation of line AB:
r=3i-2j+4k + t(-i+j+3k)
OC = i+5j-35
Any point on the line AB will have the position vector: (3-t)i + (-2+t)j + (4+3t)k <--- let this point be OD
CD=OD-OC = (2-t)i + (3+t)j + (7+3t)
Now you have two direction vectors: CD and AB
CD.AB=0 because they're perpendicular
-(2-t)+(3+t)+3(7+3t)=0
11t=-22
t=-2

Substituting t in CD
CD=4i+j+k
|CD|=3(2)^1/2= 4.24

 

[abbey789]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf
Question 5 PLEASE