Mathematics: Post your doubts here!

[Namehere]

I'm weak in complex numbers especially these loci stuffs so ahmed abdulla if you can solve that complex number question, please tag me so that I'm informed

Yes please someone solve that complex number question, if possible giving explanations.
Thanks!

 

[M Haseeb Javed]

yes

A2 level ?

 

[hamza.k143]

Can someone please tell me how to do May/June 2010 P31 Q9?
QP: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_31.pdf
MS: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_31.pdf

It is easy you just take out the gradient by quoitent rule and the reverse it for the gradient of normal and then put the point(x,y) u wuill get it

 

[Rahma Abdelrahman]

It is easy you just take out the gradient by quoitent rule and the reverse it for the gradient of normal and then put the point(x,y) u wuill get it

Part i is okay, I couldn't do part (ii).

 

[Aamir Bilal Syed]

The points A and B have position vectors, relative to the origin O, given by
−−→OA = i+2j+3k and −−→OB = 2i+j+3k.
The line l has vector equation
r = (1−2t)i+ (5+t)j+ (2−t)k.
(i) Show that l does not intersect the line passing through A and B.
(ii) The point P lies on l and is such that angle PAB is equal to 60◦
. Given that the position vector
of P is (1 − 2t)i + (5 + t)j + (2 − t)k, show that 3t
2 + 7t + 2 = 0. Hence find the only possible
position vector of P.

I solved the question but for part (ii) I got t = -2 and t=-1/3. What I don't understand is why do we reject t = -1/3 and use t=-2 to find the position vector of P?

 

[sudeep1097]

I can't solve 8 (b). Can anyone help me with it. If you are curious then this is from w_13_qp_31. I don't know how to find least value of |z-w|

 

[sumeru]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_62.pdf
Q.no.3...(ii)....anyone any idea?

 

[Aishvarya.s]

Hi can someone help with this question?
dy/dx=y-(4-y_.This question is from m/j 2005 p3 q8

Thanx in advance

 

[marimin]

please explain question 6(1) http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_3.pdf

 

[sudeep1097]

please explain question 6(1) http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w07_qp_3.pdf

It means you have to draw a graph for the equation and show that it intersects with x-axis at only one point.

 

[AgentBlank000]

Agent blank p3 p1?

Paper 4 actually, mechanics M1

 

[Hassan Ali Abid]

Is there anyone who knows about any good maths book which should contains some difficult questions of complex no. ...just like the questions which are in mayjune 13 papers.??????????

 

[mak kings]

plzz sm explain my doubt!!

 

[periyasamy]

Hi guys.Anyone can help me with the diff of this question.Thanks a lot.....
Its question 8 from oct nov 12(31)

 

[midha.ch]

Hi guys.Anyone can help me with the diff of this question.Thanks a lot.....
Its question 8 from oct nov 12(31)

 

[periyasamy]

Thank u..........

 

[Namehere]

I can't solve 8 (b). Can anyone help me with it. If you are curious then this is from w_13_qp_31. I don't know how to find least value of |z-w|

Yes please someone explain this question with explanations for every step. I know how to do the diagram, im just having trouble finding the least value for z-w.

 

[sitooon]

Try this midha.ch
Obtain A =1
Obtain B = −1, C = 2, D = 0

 

[salvatore]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
I have some problems with qn no. 5
In (i), how do I sketch the locus in an argand diagram?
(ii) I just can't solve this question. Please help me understand the working

I'll be grateful for any help provided.
Thanks

 

[sudeep1097]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
I have some problems with qn no. 5
In (i), how do I sketch the locus in an argand diagram?
(ii) I just can't solve this question. Please help me understand the working

I'll be grateful for any help provided.
Thanks

5(i)
From what i have learned. for |z-i|=2 draw circle with center at 0,i. z is at o,o and -i means that now center point is 0,i if it was +i then center point would be 0,-i just opposite. Same for real numbers i.e |z-1| would mean starting point is 0,1. Now the 2 is radius. SO |z-i|=2 means draw circle with radius 2 and center 0,i. modulus of imaginary number is a circle.