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Thanks man .I get it...Thanks a lot ..
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It absolutely can be greater than 1. Coefficient of friction is actually tan of the angle of friction. And tan can be greater than 1.Can the co efficient of friction be greater than 1?
Our teacher said it can't be but in a past paper question the coefficient of friction is 1.62 so m a li'l confused :/
Suchal Riaz
-0.3somethingwhats the other value
Im soo sorry i late but lemme tell uOct nov 13 varient 32 question 3 and 4 :/ Aly Emran View attachment 39374
Oww its okay Alo ....i got it nw !!!Im soo sorry i late but lemme tell u
Do it through integration by parts
Remember!!
Take ln x as first function
f= integration symbol
=fLnx*x^-1/2
=lnx*2x^1/2- 2f(x^1/2* x^-1)dx
Its too hard to type in math lang
I hope u can now do it from this point
Qstn 4 was hard i lost all marks cox of this :/
Do it like dx/dy and dy/dx
And then the product rule will be used
Sorry i cant type the long answer :/
Im using mobile :/
Yeah I was doing the same paper thanks alotIt absolutely can be greater than 1. Coefficient of friction is actually tan of the angle of friction. And tan can be greater than 1.
In 2010 question it's value was 1.62. So it can be greater than 1. There is no reason why it can't be.
32ln4-8ln2
8 into 4 ln4-8ln2
8ln256-8ln2
8(ln256/2)
8ln128
8ln2*7
56ln2
haha yes, the same thing...Or you can say 32ln4 - 8ln2 = 32ln2^2 - 8ln2 = 64ln2 -8ln2 = 56ln2. Maybe a bit shorter?
umm i'm sorry wat??Sorry for that it means sin power of 3then u write a t beside it.Dont get confused its not sin power of 3t.
No its not equal to 1.Here look at the pic.umm i'm sorry wat??
well u can see it this way
(Sint)^3 + (Cost)^3
is it equal to 1??
for you every question will be difficult one.I havent done all the papers but I'll look for difficult ones :/
for you every question will be difficult one.
Can anyone please give me a list of difficult questions before 2009 of M1 and P1. I will answer them and post their solutions here. i mean really difficult question. So other people can learn from my worked solutions and i learn something while doing them. anyone please. Godfather asma tareen ZaqZainab @AnyOneWhoHadDoneM1AndP1
View attachment 39473
part iii please
lolView attachment 39473
part iii please
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