Mathematics: Post your doubts here!

[Thought blocker]

no. and i won't. its not neat. i did it in parts. in different locations.

:'(

 

[sumeru]

View attachment 39587

plz solve this quest and explain too

Since the line lies in the plane, the product of direction of line and the plane's normal must be zero.....so, you'll get one equation from this...and similarly, the points (4,2,-1) lies in the plane...so they must satisfy the equation of the plane....put these values in x,y,z you will get another equation.....solve them and you will get the respective values...

 

[ZaqZainab]

i have done after 2010. and i will do 2013 on the last day.

same plans

 

[Thought blocker]

same planes

Plans*

 

[Lostsoul]

Help required please
May June 2008 Paper 3: 5, 7, 8 part ii and 10 part ii
October November 2008 Paper 3: 5ii, 6ii, 7ii, 8ii and iii, 9i and ii, 10ii, iii and iv.
JazakAllah in advance. All the best for 20th May

May June 2008:http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s08_qp_3.pdf

Oct Nov 2008:http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_qp_3.pdf

 

[ZaqZainab]

i want before 2009
and i did those questions wrong because i wasn't in mood of doing anything.
after question 3 my all questions are correct. and it was not a difficult paper.
a good paper is one from which you can learn something. where the examiner can trick you, even for a moment.
but P1 is all like find max point, find point of intersection find area under graph etc
i have been doing these kinds of questions for two years

oh no wonder you are a genius i have been doing this question for 5 months

 

[ZaqZainab]

:'(

what paper is it?

 

[daredevil]

Since the line lies in the plane, the product of direction of line and the plane's normal must be zero.....so, you'll get one equation from this...and similarly, the points (4,2,-1) lies in the plane...so they must satisfy the equation of the plane....put these values in x,y,z you will get another equation.....solve them and you will get the respective values...

can u solve it if possible? bcz i hav tried and i can only get as far as getting one equation in b and c ... after that i cant seem to grasp it...

 

[Thought blocker]

what paper is it?

2011 p12

 

[ZaqZainab]

2011 p12

i will do it when i am free

 

[Thought blocker]

i will do it when i am free

ty

 

[ZaqZainab]

oh no wonder you are a genius i have been doing this question for 5 months

i learned something idk about you as you have been solving from 2 years but here
P and Q are the centers of the circle

 

[Suchal Riaz]

View attachment 39643
i learned something idk about you as you have been solving from 2 years but here
P and Q are the centers of the circle

no other info is given?

 

[Thought blocker]

no other info is given?

Yeah, thats bit hard to solve

 

[asd]

Oct Nov 2007, Q7, part (ii) Why are we supposed to use the radian mode instead of degree mode?
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_3.pdf

 

[daredevil]

How do we find out the perpendicular distance from a point with a position vector P to a line??
P.S. the equation of the line is given.

 

[ZaqZainab]

no other info is given?

No other but by now you might have known that RS is a tangent and UT too

 

[daredevil]

someone plz do this integration !! >__<

 

[sumeru]

How do we find out the perpendicular distance from a point with a position vector P to a line??
P.S. the equation of the line is given.

I will attatch the solved one for that vector question after a while...so don't worry

 

[sumeru]

View attachment 39658

someone plz do this integration !! >__<

cos4a=1-2sin^2(2a)
2sin^2(2a)=1-cos4a
sin^2(2a)=(1-cos4a)/2
Now integrate it.......