Mathematics: Post your doubts here!

[midha.ch]

I said you na... Din't you got me ?

where? i forgot :/

 

[Thought blocker]

where? i forgot :/

Wait lemme send you again..

 

[Thought blocker]

where? i forgot :/

I dont know this method is correct or not
We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation,
So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2,
similarly,
We know have to find x2 and y2, we have x1 y1 and midpoint
so (x1,y1, + x2,y2)/2 = midpoints
=(-1,3 + x2,y2) = 2(3,9)
=(-1,3 + x2,y2) = (6,18)
x2=(6-(-1))=7
y2=(18-3)=15

so reflection on (7,15)


T H I S R E A L L Y W O R K S


Got it ?

 

[midha.ch]

I dont know this method is correct or not
We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation,
So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2,
similarly,
We know have to find x2 and y2, we have x1 y1 and midpoint
so (x1,y1, + x2,y2)/2 = midpoints
=(-1,3 + x2,y2) = 2(3,9)
=(-1,3 + x2,y2) = (6,18)
x2=(6-(-1))=7
y2=(18-3)=15

so reflection on (7,15)


T H I S R E A L L Y W O R K S


Got it ?

Got it!! thanks

 

[Thought blocker]

Got it!! thanks

Sachi ? Ki aisey hi ha boldiya ? :/

 

[midha.ch]

Sachi ? Ki aisey hi ha boldiya ? :/

na! its actually the right way!! Yohoho! you improved!
see now u can even solve my doubts! (Y)

 

[Thought blocker]

na! its actually the right way!! Yohoho! you improved!
see now u can even solve my doubts! (Y)

Thanks to you, I am not getting less then 70 in any paper

 

[omaaaar]

How to integrate 81(2x+3)^-2
Please show complete working not able to understand how to integrate a function

 

[Thought blocker]

How to integrate 81(2x+3)^-2
Please show complete working not able to understand how to integrate a function

http://calculus-calculator.com/integral/
Open this site, and you'll get to know how to ace integration

 

[omaaaar]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_12.pdf
Q10 part two what do we have to do

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf
Q10 part two what do we have to do

part i)
To get f(x), Integrate dy/dx

partii)
if d2y/dx^2 > 0 it is minimum value, here put x = 2 in ur d2y/dx^2 you get Value > 0 then it is minimum point

 

[A*(a*)]

anyone who can solve part (ii) of this question?
https://www.xtremepapers.com/community/threads/p3-complex-numbers-challenging-question.33263/

 

[A*(a*)]

and also how are A and B equal to 2 in this question?
my answer for partial fraction is A=B= 1/1800

 

[Suchal Riaz]

can anyone explain what are improper integrals???
Suchal Riaz usama321 Saad Mughal

integrals with one limit such that the integral aproaches a limit(not one absolute value)
such as one of it is infinity.
http://tutorial.math.lamar.edu/Classes/CalcII/ImproperIntegrals.aspx

 

[Saad Mughal]

can anyone explain what are improper integrals???
Suchal Riaz usama321 Saad Mughal

Integrals with either infinite as one of the limits or a limit that tends to infinity (e.g. for 1/x^2 integral, a limit of 1-0, where 0 tends it to infinity).

 

[Suchal Riaz]

such as this

 

[danial 234]

thankss Saad Mughal Suchal Riaz
i think there isnt much of it in papers!! :/

 

[Suchal Riaz]

thankss Saad Mughal Suchal Riaz
i think there isnt much of it in papers!! :/

but it ain't difficult. a little bit of common sense. like 1/infinity--->0.

 

[robinhoodmustafa]

part i)
To get f(x), Integrate dy/dx

partii)
if d2y/dx^2 > 0 it is minimum value, here put x = 2 in ur d2y/dx^2 you get Value > 0 then it is minimum point

omaaaar

Let Dy/Dx =Fx

First Derivate the x+ 4/x^2 wali equation to get F'x
and insert F'x = 0 and calculate the value of x (which is 2)

than double derivate and insert x=2 in it and you will have a value ( 3/2) with is greater than 0
greater than 0 is minimum nature
than add x=2 in the first wali eq ( x + 4/x^2 ) and you will get the minimum gradient.

 

[Saad Mughal]

thankss Saad Mughal Suchal Riaz
i think there isnt much of it in papers!! :/

It hasn't come yet in CIEs.

I was practicing OCR papers and found questions related to it, here they are if you want to practice: