Mathematics: Post your doubts here!

[Ayeshak93]

Q5

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_62.pdf

Q6 part (iii) .. can someone explain and clear my doubt please

what is the difference if we did all together and then subtract it from 12!
or we put them as 8 Items next to each other and we have 9 places to place each H tree .. so 9P4 x 8!
Please someone explain me ASAP thanks !

 

[A star]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_31.pdf Q8 (ii) Rutzaba

 

[A star]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_31.pdf Q8 (ii) Rutzaba

 

[Rutzaba]

Part 5 ii again Rutzaba (sorry for tagging, but due to quick response I am really really really glad)
Yess More prayers coming!View attachment 42627

k=1/7?

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf Q8 (ii) Rutzaba

iterative formula yad nhi

 

[Rutzaba]

how the gradient of AC is -1/2 plz help View attachment 42725

this is p1 isnt it?

 

[A star]

Rutzaba can you please solve Q9 (ii) same paper

 

[Rutzaba]

Rutzaba can you please solve Q9 (ii) same paper

ul have to wait

 

[Browny]

Hello, do you know,
-how to use mid points and frequencies to find the mean in above cumulative frequency graph?
-how to find sd (standard deviation)for A and B ?
Marking scheme answer

 

[Rutzaba]

ummm do it ^__^
thanks in advance ^__^

seeu got the value of t as 1.2765
t= tanx
1.2765 =tan x
x= tan inverse of 1.2765
one ans is 0.905
let this be alpha
tan is +ve in the first and the third quadrant
in the third quadrant pi +alpha
=4.04 radians but the range says tha answer shudnt be greater than pi
so 4.04 minus 2pi imagine the line having gone back past the 2nd quad the frst quad then the fourth quad then again it comes to the third quad a whole circle= 360degrees = 2pi
thats y we minused
4.04- 2pi =-2.24 rads

 

[Rutzaba]

Rutzaba can you please solve Q9 (ii) same paper

1 - (√2)i was a second root of the equation. So you now have
p(x) = (x - 1 -√2 i)(x - 1 + √2 i) q(x)

p(x) = (x^2 - 2x + 3) q(x)

where q(x) is now a quadratic polynomial.

Just use long division to divide p(x) by (x^2 - 2x + 3)

You should find
q(x) = x^2 + 2x + 2

Use the quadratic formula to find the remaining two roots.

 

[Rutzaba]

And also,
View attachment 42722
its the same year, Q10. I cant solve (ii)b

papers link?

 

[A*(a*)]

papers link?

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_33.pdf

 

[A star]

1 - (√2)i was a second root of the equation. So you now have
p(x) = (x - 1 -√2 i)(x - 1 + √2 i) q(x)

p(x) = (x^2 - 2x + 3) q(x)

where q(x) is now a quadratic polynomial.

Just use long division to divide p(x) by (x^2 - 2x + 3)

You should find
q(x) = x^2 + 2x + 2

Use the quadratic formula to find the remaining two roots.

do you remember it from A levels or just seem babyish due to uni math ?

 

[Rutzaba]

i dunno wat u think of uni maths as... but its extremyly rubish a right pain in the.... it has rusted my maths badly and half the formulas in intermediate we dint even have in our course

 

[A star]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_33.pdf
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_ms_33.pdf
Q4) is the ms wrong i am getting y=1/2 (x^2+4)^3

 

[Rutzaba]

do you remember it from A levels or just seem babyish due to uni math ?

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_33.pdf

jab tak tum is ka question solve kro
help him a star ive frgtn how to do thias

 

[Rutzaba]

yes ms is wrong there is a cube

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_ms_63.pdf
Q2