Mathematics: Post your doubts here!

[krishnapatelzz]

part iii and iv

 

[krishnapatelzz]

both parts

 

[krishnapatelzz]

 

[Thought blocker]

View attachment 61956

chck whats app

 

[amina1300]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Assalamoalaikum!!

UPDATE: Link to Sequences Help by destined007 added!

help in this question
MECHANICS QUESTION:

The highlighted part cant it be made into a right angled triangle to find the length of the slope( the hypotenuse)?? because in some paper it was used to find the length and if it is done in this q we get the wrong answer.

 

[krishnapatelzz]

help in this question
MECHANICS QUESTION:

The highlighted part cant it be made into a right angled triangle to find the length of the slope( the hypotenuse)?? because in some paper it was used to find the length and if it is done in this q we get the wrong answer.

you are asking if u can take 65 has hypotaneous ? it is only a ratio , for example 32/130 you will get the same angle .

 

[SpawnX-1200]

Hi folks I need some help with the question attached. I'm stuck on the last part why is the answer 18 decimal places?

 

[Aathif Shaffy]

How to do the part B

 

[shingiechingz@8]

How to do the part B
View attachment 61982

well obviously from eqn 1 u get y^2=32/x and from eqn 2 y=x^(-3)... and substitute eqn 2 to eqn 1 to get x^5=1/32 so x= 1/2 and y=8

 

[Aathif Shaffy]

well obviously from eqn 1 u get y^2=32/x and from eqn 2 y=x^(-3)... and substitute eqn 2 to eqn 1 to get x^5=1/32 so x= 1/8

Sorry for the noob question but how can this be-

x^-3=/32/x
to x^5=1/32?

 

[shingiechingz@8]

Sorry for the noob question but how can this be-
View attachment 61983
x^-3=/32/x
to x^5=1/32?

square both sides so x^(-6)=32/x
and multiply both sides by x^6 and divide both sides by 32

 

[areeba240]

(ii)..............plzz explain

 

[shingiechingz@8]

help #6(iii)

 

[Shin lol]

Sorry for the noob question but how can this be-
View attachment 61983
x^-3=/32/x
to x^5=1/32?

√(32/x)=x^-3
(32/x)^(1/2)=1/x^3
(32/x)=(1/x^6) this becomes to the power 6 when root oges other side
then 32x^6=x
divide the equation by x
32x^5=1
x^5=1/32
x=5√1/32 that is 5 power root
x=1/2
therefore you will get it.

 

[happiest]

Can someone solve Q7?

 

[student2]

Cn sm1 pls pls pls xplain hw 2 do ths? 2nd part

 

[areeba240]

how will we know that we need to use continuity correction in a question.
for example in 9709/s16/63 qtn 4(ii)

 

[Thought blocker]

how will we know that we need to use continuity correction in a question.
for example in 9709/s16/63 qtn 4(ii)

When you use a normal distribution to approximate a binomial distribution

 

[Thought blocker]

View attachment 62016

Cn sm1 pls pls pls xplain hw 2 do ths? 2nd part

Let the polynomial be p(x)
So find p(two) = 0 and
find p'(two) = 0

equate it and solve it

 

[student2]

Let the polynomial be p(x)
So find p(two) = 0 and
find p'(two) = 0

equate it and solve it

thnx. bt hw did u knw hw 2 do that? sry fr the bother