Mathematics: Post your doubts here!

[XPFMember]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

A(3,1) lies on the curve(x-1)(y+1)=4. A line through A perpendicular to x+2y=7 meets the curve again at B. Find the coordinates of B.
The answer to this with me is (0,-5)

 

[XPFMember]

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sorry for that writing.. difficult to write on PC...

 

[destined007]

Re: URGENT HELP NEEDED MATHS

Plz help for num 3 and 4

Thanx in anticipation..

 

[destined007]

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Help needed, cant solve that =(

Please...

 

[destined007]

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anyone knows how to differentiate when we are using graph and squaring method of set of values? please help

what do you mean??

 

[slayers]

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Hey I have Some Confusion ?
Do i always have to answer in three significant figures ?
esp for eg if the answer is 24283
do i have to write it as 24200 ?
Guys tell me?

 

[destined007]

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Hey I have Some Confusion ?
Do i always have to answer in three significant figures ?
esp for eg if the answer is 24283
do i have to write it as 24200 ?
Guys tell me?

Always read the instructions on the first page of your question paper. it says give non exact value to 3 sig fig. 24283 is an exact value so you need not round it off. However if the answer is 24.5798 you need to round this one.
One more thing, always use the original, unrounded values in the coming parts of your question.

 

[VelaneDeBeaute]

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AoA !!
I need help with these three questions

 

[abcde]

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AoA !!
I need help with these three questions

Second question first!
2. Angle AOB = 2/3 pi rad.
=> Reflex AOB = (2 pi - 2/3 pi) = 4/3 pi
=> Angle AOX = 1/2 x 4/3 pi = 2/3 pi
OAX = OXA (base angles of isos. triangle)
=> OXA = 1/2 (pi - 2/3 pi) = 1/6 pi.
Therefore, AXB = 2 x 1/6 pi = 1/3 pi radians.
I'll look up the other questions later.

 

[abcde]

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AoA !!
I need help with these three questions

First question:
Using Sine Rule,
2/ sin x = 3/ sin 2x
=> sin 2x/sin x = 3/2
sin 2x = 2 sin x cos x (IDENTITY)
=> 2 cos x = 3/2
=> cos x = 3/4
=> x = 41.4*
Angel ACB = 180 - 3x = 180 - 3(41.4) = 55.8*.
The side opposite angel 41.4* is 2 cm. Since AB is opposite angel ACB, which is 55.8* (greater than 41.4*), it must be greater than 2 cm!
Third question
ACB = 90*
=> cos x = AC/ 2r
=> AC = 2r cos x.
cos 2x = cos^2 x - sin^2 x (IDENTITY)
=> cos 2x = cos^2 x - (1 - cos^2 x)
Therefore, cos 2x = 2 cos^2 x - 1.

 

[1357913579]

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please solve these problem in confusion urgently requiring

 

[1357913579]

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please solve these problem in confusion urgently requiring

 

[1357913579]

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accually the pics up got unarranged so last one is first and first is last middle did not change. and another doubt please help as soon as possible.

 

[IgoforA]

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can anyone help me with this trigoooo???

 

[destined007]

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please solve these problem in confusion urgently requiring

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

please solve these problem in confusion urgently requiring

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

accually the pics up got unarranged so last one is first and first is last middle did not change. and another doubt please help as soon as possible.

 

[destined007]

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can anyone help me with this trigoooo???

 

[bamteck]

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URGENT HELP NEEDED FOR No. 9 and 10

Thank You in anticipation =)

 

[Sidma khan]

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HEy!! Can u plz help me out , i dont know a shit about Permutation and Combination...

i really need help