Mathematics: Post your doubts here!

[parthrocks]

can someone who is a genius or knows this help me out...m stuck!!!!PURE MATHEMATICS 2 and 3 a LEVELS!!!!PLZZZ ATTACH A SCAN IF POSSIBLE.....PLZZZZZZZZZZZZZZZZZZ......YA YOU!!!

iT IS CHAPTER 3 THATS LOGARITHSMS....HELPE PLZZZ ASAP!!!

 

[Amy Bloom]

iT IS CHAPTER 3 THATS LOGARITHSMS....HELPE PLZZZ ASAP!!!

I'm sorry i'm very short of time. I tried to solve only question 6 and 10 (a) since you need solutions very quickly.
I would request u to post again the values for numbers 7 and 8 because the powers are not well visible.
See attached file and if i've got the wrong answer, please do tell me, i'll go through it again.
For question 10, follow the same steps for the other parts.

 

[Lyfroker]

Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).

help please

 

[Amy Bloom]

Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).

help please

That's a hard one!
Maybe it has to do with parametric equations, don't u think?

 

[leosco1995]

Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).

help please

A quick search on Google gave me this: http://www.mymathforum.com/viewtopic.php?t=23065&p=92079

 

[leadingguy]

Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).

help please

points lieing on a circle means the distance from the centre to these points will be same.
check that out prove that out.

 

[smzimran]

can someone who is a genius or knows this help me out...m stuck!!!!PURE MATHEMATICS 2 and 3 a LEVELS!!!!PLZZZ ATTACH A SCAN IF POSSIBLE.....PLZZZZZZZZZZZZZZZZZZ......YA YOU!!!

All these questions have the same logic:

Q4 : Put the expression for Sn and equate it to 3 million in question4



As for the other questions, show me your working , i will pinpoint the mistake, its lengthy and i dont have a scanner !

 

[smzimran]

Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).

help please

If the three points lie on the circumference of a circle there distances from the centre (2,0) must be same [RADIUS ]

Find the distance b/w (7,12) and (2,0)

Find the distance b/w (-3,-12) and (2,0)

Find the distance b/w (14,-5) and (2,0)

These three distances must be same!

 

[Udam Senadheera]

Thanks for Posting this..It really helped me. The site was awesome

 

[smzimran]

This is a solution to a question asked by parthrocks :

 

[smzimran]

Another question by parthrocks :

 

[parthrocks]

plzzz help me with this:_
http://www.mediafire.com/view/?4d6mhb6ag9wdtoe# question number 5 and 7
attach scan plzzzzzzzz frinedss...

 

[smzimran]

plzzz help me with this:_
http://www.mediafire.com/view/?4d6mhb6ag9wdtoe# question number 5 and 7
attach scan plzzzzzzzz frinedss...

Q5 :

 

[GorgeousEyes]

O is the center of the sector OAB. CD is another arc, with center O and radius r cm. DB = 2cm. If the area of ABDC is one-third the area of the sector OCD find the value of r ?
I don't know how to answer this , so could u help ?

 

[VelaneDeBeaute]

O is the center of the sector OAB. CD is another arc, with center O and radius r cm. DB = 2cm. If the area of ABDC is one-third the area of the sector OCD find the value of r ?
I don't know how to answer this , so could u help ?

I replied in the conversation but assuming you didn't get it, i'm doing it here again
http://www.mediafire.com/?sd06xlzb4x2tcft <= This was the plan diagram i made.

Now for the solution!
The area of OCD = 1/2 * r^2 * theta
The area of OAB = 1/2 * (r + 2)^2 * theta
So,
area of ABDC = 1/2 * (4r + 4) * theta
Now if you equate area of ABDC to 1/3 area of OCD
you'll get
r^2 - 12r - 12 = 0
and the answer the calculator gives after solving is 12.93
​

 

[john10]

hey guys plz help me in this question.

 

[princesszahra]

at stationary point dy/dx =0

 

[parthrocks]

hey guys plz help me in this question.

Yes my friend i have done something for you!!!

 

[parthrocks]

hey guys plz help me in this question.

bro both the parts to the questions have been done...and best of luck if u dnt understand anything plzzz ask me and plzzz help me with other sums which i post....plzz

 

[GorgeousEyes]

I replied in the conversation but assuming you didn't get it, i'm doing it here again
http://www.mediafire.com/?sd06xlzb4x2tcft <= This was the plan diagram i made.

Now for the solution!​

The area of OCD = 1/2 * r^2 * theta​

The area of OAB = 1/2 * (r + 2)^2 * theta​

So,​

area of ABDC = 1/2 * (4r + 4) * theta​

Now if you equate area of ABDC to 1/3 area of OCD​

you'll get​

r^2 - 12r - 12 = 0​

and the answer the calculator gives after solving is 12.93​

​

I didn't see it , Thank you a lot . really appreciate your help