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I did what my teacher told me to. I do like mechanics better. But now my stats paper is within a week so yeah, nothing can be done- except we can pray. So pray that I do really well in it.then u should of done M2
advice: never base ur future on someone else even if its a teacher. do what u see is the best for u..u should of done M2 if u thought its better for u but what happened has happened already and no worries if u studied hard enough den hopefully u gonna owwnnnnn dat paperI did what my teacher told me to. I do like mechanics better. But now my stats paper is within a week so yeah, nothing can be done- except we can pray. So pray that I do really well in it.
i will pray for u!!So, it will be 2 on the imaginary axis and nothing on the real... And then?
u do know whats argument. ??
argument is the angle between the vector and the positive x-axis...angle between vector 2i and positive x-axis is 90 i.e. pi/2
Yeah, I got it after you sent the picture... I was out of practice so didn't quite remember... Thank you!
anytime ..Yeah, I got it after you sent the picture... I was out of practice so didn't quite remember... Thank you!
advice: never base ur future on someone else even if its a teacher. do what u see is the best for u..u should of done M2 if u thought its better for u but what happened has happened already and no worries if u studied hard enough den hopefully u gonna owwnnnnn dat paper
Yep! I got it 100%, thanks to u. Can u solve another question if u r in the mood?
let me see..Yep! I got it 100%, thanks to u. Can u solve another question if u r in the mood?
Its Q 9 part ii) of this paper
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_3.pdf
Yep! I got it 100%, thanks to u. Can u solve another question if u r in the mood?
Its Q 9 part ii) of this paper
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_3.pdf
just find normal of OAB in normal way..Oh its easy... if you have done part i u must have found direction vector (normal vector) of the plane ABC .. in part (ii) just find normal of OAB and dot it ...
if u can visualise u shall see that normal of OAB is (0,0,1) ( just for simplicity)
dont fret if yu dont get what I said in my visualise part
u sure yu got it 100%..?Thanks!
tip:Thanks!
nooo... but I'm figuring it out...
Okay! How do we find the normal of OAB?
I know its little untidy..but hope u get it..
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