Mathematics: Post your doubts here!

[Esme]

does any body have MATHS P3 VECTORS notes ?? please i need help urgent ??

 

[WayneRooney10]

That's because you'll write it as cos x = +- (5/8)^1/4
just like for square root, you write +-(square root)...
So you'll have x= cos^-1 ( positive (5/8)^1/4 ) and x=cos^-1 (negative (5/8)^1/4)
This should give you 4 different values of x.

Ohhhhhh! Yup. Thanks a lot mate!

 

[fishfish]

is this S1 maths?

 

[Esme]

Ohhhhhh! Yup. Thanks a lot mate!

You're welcome

 

[Esme]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_33.pdf
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_ms_33.pdf

Q6ii) How should we find (a+bi)? I made an Argand diagram and so found it from the sketch. But do we have to show any calculations for this ? If yes, then how to calculate a+bi ?

Alice123
MustafaMotani

or anyone ?

 

[scouserlfc]

it is very hard

lg [(3x)^(lg3)] = lg [(4x)^(lg4)]
lg3 x lg3x = lg4 x lg4x
lg3 x (lg3 + lgx) = lg4 x (lg4 + lgx)
(lg3)^2 + lg3lgx = (lg4)^2 + lg4lgx
(lg3)^2 - (lg4)^2 = lg4lgx - lg3lgx
(lg3 - lg4) (lg3 + lg4) = lgx (lg4 - lg3)
-(lg4 -lg3) (lg3 + lg4) = lgx (lg4 - lg3)
-(lg3 + lg4) = lgx
-lg12 = lgx
lg(1/12) = lgx
x = 1/12

thanks a lot May ALLAH bless you and allow u to help others as u just did thanks

 

[MustafaMotani]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_33.pdf

Q6ii) How should we find (a+bi)? I made an Argand diagram and so found it from the sketch. But do we have to show any calculations for this ? If yes, then how to calculate a+bi ?

Alice123
MustafaMotani

or anyone ?

sis marking scHeme tells us everything ...
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius

 

[iKhaled]

sis marking scHeme tells us everything ...
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius

how do we find the mid-point of w and w^2

 

[WayneRooney10]

Anybody got notes for P3 integration?

 

[TaffsAsLevel]

Any one get this? What mistake have I done? Mark scheme said s=2 but I got 1.4?

 

[xhizors]

Q6
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_31.pdf
whats your answer?

 

[applepie1996]

Any one get this? What mistake have I done? Mark scheme said s=2 but I got 1.4?

you did everything correct except you have to subract x=1+s with -3 as shown in the question (r-3i) which means r has to subtracted from vector (3,0,0) j and k are zero in this case

 

[cool Asviva]

s1
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_63.pdf
4 ii part.
anyone plz help me....i dnt know how to solve it.

 

[applepie1996]

Q6
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
whats your answer?

y=(x^2-4)/(x^2+4)

 

[Esme]

Anybody got notes for P3 integration?

 

[Esme]

Q6
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
whats your answer?

y=(x^2 -4)/(x^2 +4)

 

[Muhammad Muneeb]

i have a question, the paper its from isnt here on xtremepapers, its june 2002 paper 6, q5,
question is: the digits of number 1223678 can be rearraged to give many different 7 digit umbers. find how many 7-digit diferent numbers can be made if
i) there are no restrictions on the order of digits
ii) the digits 1,3,7 are (in any order) are next to each other
iii) these 7 digit numbers are even.

any help?

 

[Esme]

sis marking scHeme tells us everything ...
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius

I got the diameter and radius... I was wondering how would we find out the mid- point and I just understood!! We had to use the coordinate geometry formula for mid-point of the two points! Can't believe I didn't think of that before ! Thank you soo much. May Allah bless you and grant you success in this life and in the Hereafter

how do we find the mid-point of w and w^2

 

[xhizors]

y=(x^2-4)/(x^2+4)

can u share your working plz..

 

[Esme]

can u share your working plz..