Mathematics: Post your doubts here!

[Thought blocker]

I am very dull at maths............................pls smeone hlp me out

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Full paper solved mehria ZaqZainab
Correct me please

 

[Talha Irfan]

U are considering that there are two chemicals only that should be placed on the four positions.but when we are arranging the rest we are placing two more on those 4 places!

please elaborate with calculation/example if you can (that is, where am i going wrong in my approach)

 

[Angelina_25]

Oct nov 13 varient 61 q#6 part ii) and iii)
Im not that good in permutation and combination so a detailed explanation will be better ....thanks for ur help!!!

 

[itallion stallion]

omg i did nt get this too and i cant find the attachment for part (i) and part (ii) a
can u check your answer to part (ii) b because the right answer is 25/24
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_33.pdf Question 10
Thank you

Really sorry for that!I don't why I can't upload any file.if it's not urgent I can try later,otherwise give your id I will send their.

 

[itallion stallion]

Thank you , but for ques 8 part (ii) the answer is not zero can u check it please ??
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_33.pdf

I am getting -3/2 rather just 3/2.try asking someone else.sorry!

 

[itallion stallion]

Really sorry for that!I don't why I can't upload any file.if it's not urgent I can try later,otherwise give your id I will send their.

 

[David Hussey]

It's 1/3(3x+1)-1/3ln(3x+1) actually. =[

i got it
u=3X+1
therfore 3X=u-1

du/dx=3
so, 1/3du=dx

so now it should look like this
((u-1)/3u)du
simplify it,
1/3 - 1/3u
now integrate
u/3 - 1/3 ln u +c
therefore
3X+1/3 - 1/3 ln(3X+1) +C

 

[Haya Ahmed]

M/J_2005_P6 Q6 (ii) Please someone help me

 

[David Hussey]

if 5^X= u
what will 5^x-1 be?

 

[itallion stallion]

M/J_2005_P6 Q6 (ii) Please someone help me [/quote

 

[itallion stallion]

if 5^X= u
what will 5^x-1 be?

u/5

 

[David Hussey]

itallion, what did you do to get that?

 

[itallion stallion]

itallion, what did you do to get that?

itallion, what did you do to get that?

If U=5^x
5^x-1 can be written as 5^x multiply by 5^-1 as per indices rule so not just write 5^x as u and divide it by 5

 

[A star]

p3 please solve daredevil asd and others.............................

 

[saimcfc178]

Can you provide me with the solution of Q10 O/N p32?

 

[David Hussey]

p3 please solve daredevil asd and others.............................View attachment 40236

View attachment 40208

angle aoc= A+A+X=pie (theta=A)
aoc-pie-2A

findAC
cos A=adjacent/r
AC=2rcosA

area of sector ABC
(0.5*(2RcosA)^2*A)*2
u should get
4r^2cos^2ArA

now find the area which of the small thingy (idk what u call it)
(area of sector minus area of triangle)*2 ....because there are two of them
so
2[0.5*r^2*pie-2A)-(0.5*r*2rcosA*sinA)]
simplify and u should get
r^2(pie-2A-sin2A)

now add both the areas and equate to 0.5pier^2 and simplify it
hope it helps!

 

[Haya Ahmed]

Can you explain what happened in part ii ^_^ .. I appreciate your help

 

[Haya Ahmed]

Can you explain what happened in part ii ^_^ .. I appreciate your help

 

[Haya Ahmed]

M/J_2005_P6 Q6 (ii) Please someone help me

 

[ZaqZainab]

M/J_2005_P6 Q6 (ii) Please someone help me

we know
P((1.9-b)<x<(1.9+b))=o.8 and mean=1.9 and SD=o.15
P((1.9-b-1.9)/0.15)<((1.9+b-1.9)/0.15) = o.8
ph of (b)/0.15)+ ph of (+b)/0.1 - 1= o.8
2ph of (b)/0.15=1.8
ph of (b)/0.15=0.9
from the normal distribution graph find the z value for o.9 p if you see the small ttable giveen below it would be easier z= 1.282

(b)/0.15=1.282
b=0.1923
limits 1.9-b and 1.9+b
that is 1.7077 and 2.0923
round of to 3 decimal places