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tyil see wat i can do. need two three days to prepare for it and my net is doomed.
lets see how lucky u ppl get
circular measure definitely
trignometry probably
functions if u get reaaly really lucky
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tyil see wat i can do. need two three days to prepare for it and my net is doomed.
lets see how lucky u ppl get
circular measure definitely
trignometry probably
functions if u get reaaly really lucky
even at the uni level :xikr like why in the world do they even exists
Thank uil see wat i can do. need two three days to prepare for it and my net is doomed.
lets see how lucky u ppl get
circular measure definitely
trignometry probably
functions if u get reaaly really lucky
your in university?even at the uni level :x
you're*your in university?
well i am going for medical so i don't think so
prayers... i need em in return.Thank u![]()
I DID IT 4 U
2 is better than 1![]()
your in university?
well i am going for medical so i don't think so
did u guys have addmaths?Thank u![]()
Nups.did u guys have addmaths?
about question 10 .... shuffle through the last couple of pages... i think the solutionn to that particular question has been posted prob twice over the last pages.... see if u can find ithttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
Can any one help me with qusetion 10 please ?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_41.pdf
And question 3 in this one ?![]()
THANKS FOR THE HELPwe know
P((1.9-b)<x<(1.9+b))=o.8 and mean=1.9 and SD=o.15
P((1.9-b-1.9)/0.15)<((1.9+b-1.9)/0.15) = o.8
ph of (b)/0.15)+ ph of (+b)/0.1 - 1= o.8
2ph of (b)/0.15=1.8
ph of (b)/0.15=0.9
from the normal distribution graph find the z value for o.9 p if you see the small ttable giveen below it would be easier z= 1.282
(b)/0.15=1.282
b=0.1923
limits 1.9-b and 1.9+b
that is 1.7077 and 2.0923
round of to 3 decimal places
the answer is "the value of N approaches 1800" Thanks anyways for giving it a try.m not sure if i am right
but take an eg
when t=2
n=633
t=100
n=1800
so increasing, is it correct?
I need help pleaseI have doubts and I feel confused
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf Question2, Question6, Question7, Question8 and Question10
this is the mark scheme link
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_31.pdf
please help me !![/quote
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