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Mathematics: Post your doubts here!

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http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Q2.....
Here is the mark scheme.. http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s06_ms_1.pdf
Please don't copy the mark scheme i need answer step by step, how can you do:
tan(2x)=-3
2x= 180 - (tan^-1 (-3)) or 2x = 360 - (tan^-1(-3))
From where does the 360 and 180 come in.

Also can you calculate tan^2(x), in calculator, where as x has a value.
If yes how, i have fx-991 ES Plus,
Also does tan(x) * tan(x) = tan^2(x)
 
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sin(2x) + 3cos(2x) = 0
sin(2x) = −3cos(2x)
sin(2x)/cos(2x) = −3
tan(2x) = − 3

Now da function of tan has a period of 180° (π radians) meaning dat its value repeats after each 180° cycle.
2x = arctan(−3)
2x = −71.6°

0° ≤ x ≤ 180°
0° ≤ 2x ≤ 360°
 
Messages
639
Reaction score
3,684
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253
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Q2.....
Here is the mark scheme.. http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_ms_1.pdf
Please don't copy the mark scheme i need answer step by step, how can you do:
tan(2x)=-3
2x= 180 - (tan^-1 (-3)) or 2x = 360 - (tan^-1(-3))
From where does the 360 and 180 come in.

Also can you calculate tan^2(x), in calculator, where as x has a value.
If yes how, i have fx-991 ES Plus,
Also does tan(x) * tan(x) = tan^2(x)
Got it broo ? any doubts ?
 
Messages
129
Reaction score
203
Points
53
If u got my method then always use it, if u didnt i can explain it
I would love a bit of explaination
you said 'Now da function of tan has a period of 180° (π radians) meaning dat its value repeats after each 180° cycle.
0° ≤ x ≤ 180°
0° ≤ 2x ≤ 360°
'
Was it not supposed to be used as
2x = 360 − 143.2 , 180 − 71.6
 
Messages
639
Reaction score
3,684
Points
253
[ (1 + sinx)/cosx ] + [ cosx/(1 + sinx) ]

Take L.C.M.
[ (1 + sinx)(1 + sinx) + (cosx)(cosx) ] / cosx(1 + sinx)

Expand numerator only
[ 1 + 2sinx + sin²x + cos²x ] / cosx(1 + sinx)

Now simplify (sin²x + cos²x = 1)
(1 + 2sinx + 1) / cosx(1 + sinx)

(2 + 2sinx) / cosx(1 + sinx)

Factorize numerator
2(1 + sinx) / cosx(1 + sinx)

1 + sinx cancels
2/cosx
 
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