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yes.So this mean the onto functions only have Inverse?
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yes.So this mean the onto functions only have Inverse?
little have i done tho... excpt annoying princeali
Yar no link.Its a question from another sourcelink of the question do
little have i done tho... excpt annoying princeali![]()
dil ki awaz mai khete to retard nikal taYar no link.Its a question from another source.Its a formula like this na tan@ = 1- sth ..sth..i dont remember..btao na genius!
snapshot?Yar no link.Its a question from another source.Its a formula like this na tan@ = 1- sth ..sth..i dont remember..btao na genius!
isse pehle k apko nafrat ki awaz mile stop talking like that bachay...mujhay dil ki nahi dimag ki awaaz chahye meri jaan.
Dude, first off, you really need to cool off and let go of that khuari a bit. Give the lady some respect. Secondly, what you are asking is pretty simple. Look, you need to find the angle between a curve and a tangent, right? That would require you to know two things: The gradient of the tangent to the curve and the other is the point on the curve to which you need angle from. Next you differentiate the equation of the curve and find the gradient of that point by substitution and now all you need to know is the fact that a gradient is just simple the ratio of the height of an point to the width of it, that means,mujhay dil ki nahi dimag ki awaaz chahye meri jaan.
haha, for the last part, you first take the square root on both the sides and then go on to take the inversehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q5 pii , piii
How the heck do i find the range from domain, My freaking book sucks! ?
Generally how do you do it. I need help please.
I want part iii too, i am stuck at:
cos^2 (x)=0.6
How do you do after this or how do you calculate this thing:
x= cos^-2 (0.6)
f(x) = 2 – 5(cosx)^2http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q5 pii , piii
How the heck do i find the range from domain, My freaking book sucks! ?
Generally how do you do it. I need help please.
I want part iii too, i am stuck at:
cos^2 (x)=0.6
How do you do after this or how do you calculate this thing:
x= cos^-2 (0.6)
For C u just have to calculate x because y=o so put the value of x in equation n you'll get tge answerHow to use the vector move step?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf
Q)6)ii) coordinates of D.
oOps sorry read it wrongHow to use the vector move step?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf
Q)6)ii) coordinates of D.
Find the gradient of AD which Is parallel to BC and of DC which is parallel to AB you will get the equations then solve thm simultaneously u will get DHow to use the vector move step?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf
Q)6)ii) coordinates of D.
use midpoint formula,its really easy!How to use the vector move step?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf
Q)6)ii) coordinates of D.
Do you know how to do the question using vector move step?Find the gradient of AD which Is parallel to BC and of DC which is parallel to AB you will get the equations then solve thm simultaneously u will get D
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