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Change x to y and y to x
hence x = 5/1-3y
make y subject, you get y = x-5/3x
change y to f inverse.
Domain of f(x) is range of f inverse and vice-verse
so here domain of f(x) is >= 1 so range of f inverse would be >= 1
Range of f(x) is − 2.5 ≤ x < 0 so domain of f inverse will be − 2.5 ≤ x < 0
Sure,
Put x as 1 in f(x) you get -2.5 as lower range
how did you get y = -x/2 + pi .... we are supposed to get y = (pi-x)/2On the same graph, draw the line y = -x/2 + pi
When x = 0 y = pie, when x = 3 y = 1.64 now connect both the points
Post the question's link.
which question?
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_12.pdf
Try substituting values for more than 1 and you'll find that the values of range keep decreasing till zero and it will never touch it and by knowing the graph of the function you will be able to relate what I'm sayinghttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_12.pdf
question 9iii) How is the domain of f inverse has o ?
My mistake.
but we will get answers like 1.bla bla bla 0. bla bla bla .. how are we supposed to plot this on the graph there must be mistake somewhere plus the graph is not given in the ms so IDK WHAT TO DOMy mistake.
So, put x = 0 and get y from the eqn, and put any other value of x and get your y, and plot the graph
Take very far points on x axis and connect 'embut we will get answers like 1.bla bla bla 0. bla bla bla .. how are we supposed to plot this on the graph there must be mistake somewhere plus the graph is not given in the ms so IDK WHAT TO DO
omg are you serious ? .. since when do we get these kind of decimals .. ABNORMAL decimals !!Take very far points on x axis and connect 'em
Its the only way I do it, if you get more accurate way, do tell meomg are you serious ? .. since when do we get these kind of decimals .. ABNORMAL decimals !!
What? this is the formula
Phew, that took a while to write clearly and illustrating properly sorry for the delay
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