Mathematics: Post your doubts here!

[rackstagryan]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_12.pdf

question 11 (i)

 

[Thought blocker]

flirting with suchal BUAHAHAHAHA
anyway
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w05_qp_1.pdf
Q4 please

yes

4i)
When you solve OP.OQ you get its value as to
and use, |OP|.|OQ|cos theta = OP.OQ
you get is root 14 times root 14 cos theta = 2
so, 14cos thea = 2 ; cos theta = 1/7

ii)
q-p = 4 - 2 + q - 1 = 6
so q = 5

 

[A*(a*)]

done first part?

part (ii)

 

[itallion stallion]

done first part?[/quotes
Can u plz explain explain the second and third part of this question
Thanks

 

[Saad Mughal]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_12.pdf

question 11 (i)

When x = 0,
y = 1
Therefore, B is point (0,1).
dy/dx = 2(1+4x)^-1/2
When x = 0,
dy/dx = 2
Therefore, Gradient of normal = -1/2

Equation BC => y - 1 = -1/2 (x - 0)
2y - 2 = -x
x + 2y = 2

 

[omaaaar]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_12.pdf
Q11 part 1

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf
Q11 part 1

we can see that OQ= 20 hence Oc= 20-x
sin(0.6)=x/OC
equate both and get the answer

 

[omaaaar]

Guys I did the exam for paper 2 variant 2 IGCSE O-level and don't worry the exam IS VERY EASY ...Don't give me your email because I won't send to anyone

Bro this is an alevel thread

 

[A*(a*)]

we can see that OQ= 20 hence Oc= 20-x
sin(0.6)=x/OC
equate both and get the answer

https://www.xtremepapers.com/community/threads/p3-complex-numbers-challenging-question.33263/

 

[mehranshaikh]

papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w13_qp_32.pdf

Anyone help me with Q8. (b)? How to find the least value?
And also Q4.

 

[Suchal Riaz]

Meri dadi wapis agayi yay

flirting with suchal BUAHAHAHAHA
anyway
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w05_qp_1.pdf
Q4 please

 

[omaaaar]

I don't know which paper this question is from came in my mock paper
Question is
Sin2x=2cos2x,for0<=x<=180

 

[omaaaar]

A curve has equation y=f(x) where f(x)=x^3-2x^2+x
Find the set of values for which the gradient of a curve is less than 5

 

[David Hussey]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_11.pdf

q11)iii
we have to find the equations of OA and BC in order to find coordinates of E right?
i did that, but i am getting x as 10/13 and y as 20/13
can someone check my workings and tell me where i went wrong?
its the top part, ignore the bottom part

 

[Thought blocker]

I don't know which paper this question is from came in my mock paper
Question is
Sin2x=2cos2x,for0<=x<=180

Is answer , theta = 31.71 and 58.28 ?

 

[David Hussey]

Is answer , theta = 31.71 and 58.28 ?

can u check my doubt as well? its kinda urgent

 

[omaaaar]

Is answer , theta = 31.71 and 58.28 ?

I don't know the answers as I did it wrong

 

[Thought blocker]

can u check my doubt as well? its kinda urgent

It is a bit tough, It will need some time, and I am busy in Inorganic, sorry.

 

[Thought blocker]

I don't know the answers as I did it wrong

tan 2x = 2
tan inverse 2 = 63.43
2x = 63.43 ; x = 31.71
2x = 180 - 63.43 ; x = 58.28

 

[kitkat <3 :P]

yes

4i)
When you solve OP.OQ you get its value as to
and use, |OP|.|OQ|cos theta = OP.OQ
you get is root 14 times root 14 cos theta = 2
so, 14cos thea = 2 ; cos theta = 1/7

ii)
q-p = 4 - 2 + q - 1 = 6
so q = 5

thanks Thought blocker is fli

Darling, sup with chem ?

thanks