Mathematics: Post your doubts here!

[Thought blocker]

I don't know the answers as I did it wrong

tan 2x = 2
tan inverse 2 = 63.43
2x = 63.43 ; x = 31.71
2x = 180 - 63.43 ; x = 58.28

 

[kitkat <3 :P]

yes

4i)
When you solve OP.OQ you get its value as to
and use, |OP|.|OQ|cos theta = OP.OQ
you get is root 14 times root 14 cos theta = 2
so, 14cos thea = 2 ; cos theta = 1/7

ii)
q-p = 4 - 2 + q - 1 = 6
so q = 5

thanks Thought blocker is fli

Darling, sup with chem ?

thanks

 

[kitkat <3 :P]

yes

4i)
When you solve OP.OQ you get its value as to
and use, |OP|.|OQ|cos theta = OP.OQ
you get is root 14 times root 14 cos theta = 2
so, 14cos thea = 2 ; cos theta = 1/7

ii)
q-p = 4 - 2 + q - 1 = 6
so q = 5

thanks Thought blocker is fli

Darling, sup with chem ?

thanks

 

[Rutzaba]

Meri dadi wapis agayi yay

played nazi zombies ? cod
natch der untoten?

 

[omaaaar]

tan 2x = 2
tan inverse 2 = 63.43
2x = 63.43 ; x = 31.71
2x = 180 - 63.43 ; x = 58.28

A curve has equation y=f(x) where f(x)=x^3-2x^2+x
Find the set of values for which the gradient of a curve is less than 5
Pls solve this as well

 

[Rutzaba]

A curve has equation y=f(x) where f(x)=x^3-2x^2+x
Find the set of values for which the gradient of a curve is less than 5
Pls solve this as well

differentiate it and equate it to less than 0

 

[persandkesh]

the only difficult part in that binomial question was (c) part. here is how to do (c) part. first two are as easy as every binomial question.

Ive got 675

 

[Rutzaba]

3x^2-4x+1<5
3x^2-4x-4<0
3x^2 -6x +2x -4<0
3x(x-2) +2(x-2)<0
(x-2)(3x+2)<0
since its less than we have oopositye of the numberline value...
2<x<-2/3
sumbody confirm>?

 

[MiniSacBall]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf

q8 (i)
Full steps after
(1-cosx) (1-cosx)/(1-cos^2 x)

 

[omaaaar]

Ive got 675

Ans is 675 addition mistake has been done

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf

q8 (i)
Full steps after
(1-cosx) (1-cosx)/(1-cos^2 x)

(1-cos^2 x= a^2-b^2 = (a-b)(a+b)
denominator wud be (1+cos x)(1-cosx)

(1-cosx) (1-cosx)/(1+cos x)(1-cosx)
cancel 1-cosx

 

[biscuitbiscuit]

How do we know if the function is 1 to 1. I know it comes for only 1 mark but still someone please help out

 

[Knightmare11]

Could you prove this for me? Maths Nov 13 P3 Q.06 Part.1 !! Thanks!

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_qp_32.pdf

 

[ZaqZainab]

princeali97

 

[kitkat <3 :P]

Anyone :/

 

[Rutzaba]

Could you prove this for me? Maths Nov 13 P3 Q.06 Part.1 !! Thanks!

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_32.pdf

Phew, that took a while to write clearly and illustrating properly sorry for the delay
View attachment 41014 View attachment 41015 View attachment 41016

go back onto talha's post there u will find sol

 

[MiniSacBall]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf
Q9 iv please
I know how to find the gradient of the normal.

 

[princeali97]

princeali97

Ahaa.Youre confused.I hope this diagram explains.

 

[princeali97]

View attachment 41446 Anyone :/View attachment 41446

which question?

 

[ZaqZainab]

Ahaa.Youre confused.I hope this diagram explains.

yeah i get it now me so dumb