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Mathematics: Post your doubts here!

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How to solve trigonometrical equations within the range of -180< x <180? Is there any simple way to solve such equations easily?
Here are some examples I want to see how we can solve them
(a) (3 square root 3) sin x = cos x
(b) sin square x = 0.5
 
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How to solve trigonometrical equations within the range of -180< x <180? Is there any simple way to solve such equations easily?
Here are some examples I want to see how we can solve them
(a) (3 square root 3) sin x = cos x
(b) sin square x = 0.5
dude u already asked ths n i already replied :p lol

ok lemme tell u again :)
ive no calculator now so i wont be givin u the values..only steps though

(a) make in terms of tan
constants on one side and identity (tan) on one side
tan inverse then u get key angle
to make answer in range add or minus 360

same goes for (b) add or minus 360 to answers u get whn solving quadrants.
 
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dude u already asked ths n i already replied :p lol

ok lemme tell u again :)
ive no calculator now so i wont be givin u the values..only steps though

(a) make in terms of tan
constants on one side and identity (tan) on one side
tan inverse then u get key angle
to make answer in range add or minus 360

same goes for (b) add or minus 360 to answers u get whn solving quadrants.

Isn't tan add/minus 180?

Also for B I would rather square root the equation, giving sinx = sqrtroot 0.5. After finding x, don't forget that x can have two kinds values: x+360k and (180-x) + 360k.....
 
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