Mathematics: Post your doubts here!

[Komail Sabba']

I want 2014 papers of P1 AND M1! ..PLZZZ!

https://www.xtremepapers.com/commun...nd-marking-scheme-all-in-one-2001-2014.36824/

 

[ashcull14]

NOV 2008 P4
Q7 A particle P is held at rest at a fixed point O and then released. P falls freely under gravity until it reaches the point A which is 1.25m below O.
(i) Find the speed of P at A and the time taken for P to reach A.[3]
The particle continues to fall, but now its downward acceleration t seconds after passing through A is (10−0.3t)ms−2.
(ii) Find the total distance P has fallen, 3s after being released from O............................

 

[ashcull14]

I want 2014 papers of P1 AND M1! ..PLZZZ!

http://maxpapers.com/category/quali...l/cambridge/a-level/a-level-mathematics-9709/

 

[Haya Ahmed]

http://onlineexamhelp.com/wp-content/uploads/2012/05/9709_w11_qp_42.pdf

q6 (iii)

 

[swdj24]

p.m me your email adress i will 4rward you the notes on least and greatest values of arguments and all

cld u send it to my email too? [email protected] THANKS

 

[PlutoHuman]

Can someone please do this

 

[rachelblurr]

www.facebook.com/alvlmaths
complete solutions for Maths P1, P3, P4, P6
Still in progress but feel free to PM me questions.

 

[Komail Sabba']

Can someone please do this
View attachment 51697

x= 0.322?

 

[Wolfgangs]

http://maxpapers.com/wp-content/uploads/2012/11/9709_s14_qp_32.pdf

Can someone please tell me how Q1 was solved?

 

[Wolfgangs]

http://maxpapers.com/wp-content/uploads/2012/11/9709_s14_qp_32.pdf

Can help me with q6 part 1

 

[Ram97]

http://maxpapers.com/syllabus-mater...hment/9709_may-june-2010-all-question-papers/
June 2010 p12
Q.11 part iii iv v

 

[The Sarcastic Retard]

http://maxpapers.com/syllabus-mater...hment/9709_may-june-2010-all-question-papers/
June 2010 p12
Q.11 part iii iv v

Check Q11 here. http://8mundo.forumchitchat.com/file?id=1660235

 

[Alyjohn]

Please post solution of papers 2014 M1 (both m/j & o/n)?

 

[ashcull14]

Can someone please do this
View attachment 51697

PART 1-
sin (a+b) =sinacosb+cosasinb
*so for sin (3x) = = sin(2x + x)

= sin(2x)cos(x) + cos(2x)sin(x)
=cosx [sin(2x)cos(x) + cos(2x)sin(x)]
= 2sin(x)cos(x)cos(x) + (1 - 2sin² (x) ) sin(x)
= 2sin(x)cos² (x) + sin(x) - 2sin³ (x)
= 2sin(x) ( 1 -sin² (x) ) + sin(x) - 2sin³ (x)
= 2sin(x) -2sin³ (x) + sin(x) - 2sin³ (x)
= -4sin³ (x) + 3sin(x)
= 3sin(x) - 4sin³ (x)

 

[ashcull14]

please can someone solve it step by step?

 

[Abhay Ram]

Hi,
I'm doing trigonometry P1 and I'm stuck at Exercise 10B : Use the symmetric and periodic properties of the sine, cosine and tangent functions to establish the following results:
(a.) sin(90-theta) = cos theta
(b.) sin(270+theta) = -cos theta
(c.) sin(90+theta) = cos theta
(d.) cos(90+theta) = -sin theta
(e.) tan(theta - 180) = tan theta
How do I solve these? Please help.

 

[qwertypoiu]

Hi,
I'm doing trigonometry P1 and I'm stuck at Exercise 10B : Use the symmetric and periodic properties of the sine, cosine and tangent functions to establish the following results:
(a.) sin(90-theta) = cos theta
(b.) sin(270+theta) = -cos theta
(c.) sin(90+theta) = cos theta
(d.) cos(90+theta) = -sin theta
(e.) tan(theta - 180) = tan theta
How do I solve these? Please help.

which year is this? Just interested.

 

[The Sarcastic Retard]

View attachment 51741

please can someone solve it step by step?

P1 or P3 ?

 

[The Sarcastic Retard]

Hi,
I'm doing trigonometry P1 and I'm stuck at Exercise 10B : Use the symmetric and periodic properties of the sine, cosine and tangent functions to establish the following results:
(a.) sin(90-theta) = cos theta
(b.) sin(270+theta) = -cos theta
(c.) sin(90+theta) = cos theta
(d.) cos(90+theta) = -sin theta
(e.) tan(theta - 180) = tan theta
How do I solve these? Please help.

Remember if the digits are odd, remove sin and and cos and vice versa, in case of tan, remove tan and add cot and vice versa.
Remember ASTC graph.
(a) sin(90 - theta) = 90 is odd so add cos remove sin. 90 - thetha = A so cos theta.
(b) sin (270+ theta) = 270 is odd so remove sin add cos, 270 + theta = C so sin is -ve = - cos theta.
(e) tan(-(180-theta)) = 180 is even, so no changes. tan(-theta) = tan theta.
REST TRY OUT YOURSELF, if u still have doubts, we are here to solve them.

 

[The Sarcastic Retard]

which year is this? Just interested.

Its from textbook.