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Mathematics: Post your doubts here!

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v = 4t - 1/16*t^3
s = 2*t^2 - 1/64*t^4 + c
we know that when t=0, s=0 as well:
0 = 0 - 0 + c
c = 0
s = 2*t^2 - 1/64*t^4
Distance PQ is 64m, so we just have to find the value of t for which s=64:
64 = 2*t^2 - 1/64*t^4
t = +/-8
t = 8 (reject negative)

ii)
a = 4 - 3/16*t^2
a>0
4 - 3/16*t^2 > 0
and you do the rest :)
thnk u so much :D
 
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Not sure what subjects you're taking so I'll just tag you in Maths because the probability of you taking it is high given your name and whatnot :3
You can then explore this forum for help in your other subjects C:
BEST OF LUCK ya cutie~
Hui Yie
 
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NO.6 anyone ?
P3 mathematics
 

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Plzz Zaq sarcastic & others... help me clear my concept.
When we are ask to find the acute angle b/w the lines/planes we need to use the formula N1 * N2= |N|*|N| cosQ/sinQ
My question is when to use SinQ and CosQ when we are using this formula to calculate the Q ?
 
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NO.6 anyone ?
P3 mathematics

Hello Paresh.

Q6) I)First off, were told that perimeter of shade= 1/2 circle circumference
Find radius of shade by dropping down a perpendicular so you get this in terms of r and x. Also theta here will be 2x. Radius of shade we do cosx= Adj/r , hence adj = rcosx and so side AB= 2rcosx
Also side AC is 2rcosx
So Perimeter Shade= 1/2 Circle Circumference Get arc length = rtheta = 2rcosx 2x= 4rxcosx
Arc + AB + AC= 1/2 x 2pier
4rxcosx + 2rcosx + 2rcosx= pier
Cross r
4xcosx + 4cosx = pie Notice on left hand side cosx is a common factor

So cosx(4x + 4) = pie
Cosx= pie/(4x + 4)
X = cosinverse(pie/4x+4)

Done :) part ii) and iii) are easy and straightforward
 
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Plzz Zaq sarcastic & others... help me clear my concept.
When we are ask to find the acute angle b/w the lines/planes we need to use the formula N1 * N2= |N|*|N| cosQ/sinQ
My question is when to use SinQ and CosQ when we are using this formula to calculate the Q ?
If you use cos you will get a values which isn't the acute angle then you have to 180-(cos-1(...)) we use sin for angle between line and plan
while for angle between 2 lines of 2 planes we use sin. this is what my teacher has taught me
 
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