- Messages
- 196
- Reaction score
- 39
- Points
- 38
Uhh we made 2 simultaneous equations for the distance of 100 and 248 considering s-ut+1/2at^2
and then solved them
so a was 3 and u was 19 i think
the thing is i didnt make a simultaneous equation. i just used the average speed distance time method to prove my 2.5 m/s^2 was approx equal to 3. do u think i'll get some ecf. i then proceeded to use v^2 = u^2 -2as to find u
what distance did u get?