Maths P1 2011

[sea_princess]

I think it was 8.5, what was your answer?

 

[trk1994]

what i remember is i did 32 divide by -8 n got -4 :S:S:S

 

[trk1994]

andd in vectorrr quetion part 1 it meant its perpendicular ryteee so i multiplieddd and = to 0

 

[markskoop]

ya dat value of k is 8.5 and in dat vector question ...we hav to multiply the correspondind vector and adding it resulting to 0.i guess u would get 17/4 or sth lik dat in fraction..............

 

[phro5031]

i made the range of sinx<cos2x : 0to30 and 150 to 180 and the stationery point what was it?????

 

[djdead1]

What did u do for the second part of the vector question?

We had to find the unit vector right? AB / 28 , yeah?

 

[1357913579]

for the value of k it was 8.5 i dont remember for stationary points but for vector i remember it was 4 multiply by Ab impossible -4 as same direction so how can sign change

 

[djdead1]

for the value of k it was 8.5 i dont remember for stationary points but for vector i remember it was 4 multiply by Ab impossible -4 as same direction so how can sign change

why would it be 4 * AB ? :s

 

[1357913579]

see what you do first get AB THEN YOU BUT X MULTIPLY BY AB THEN DO ITS MODULUD MEANS SQUARE EACH VAKUES WHICH WOULD BE INTERMS OF X THEN SQUARE ROOT IT PUT IT EQUAL TO 28 SO THEN SQUARE 28 AS SQUARE ROOT FROM X VALUES WILL GO OTHER SIDE AND BECOME SQUARE SOLVE YOU WILL GET 4

 

[vaishster]

simple answer... unit vector of AB is VectorAB / 7(magnitude of vectoy)... multiply the resulting vector by 28 (magn given)... tat is the answer.. so basically all we are doin is multiplyin vector AB by 4 (28/7)

 

[sea_princess]

the question didn't ask for unit vector just the vector and I'm sure 100 %

 

[markskoop]

ya no unit vector................

 

[noga0007]

guys for the coiefficent of x ^ 2 .. I did it 400
ii) in vectors i X by 4 in AB
stationary points ..(4,4)
limits of the volume 0 to 8
perimeter 16.19 I think
value of K 8.5
value of P -4.5

and actually i wrote any shit in the question of sinx<cos2x ... and I did the GP wrong ... SILLY MISTAKE i took that difference between years 10 years only !!!!

 

[vaishster]

ya it didnt ask for unit vector
this is just method for finding out the vector in direction of ab with mag 28(4 times mag of ab(7))

 

[sarzkhan]

qs 1b) 400
k was 8.5
p was -4.5
range was x<30, x>150
perimeter was 16.2
stationary points (4,4)
in ap: d was -3
l was 57
diff was 420
gp: 65700 probably
and the year diff was 11

 

[1357913579]

and for ap for only posotive no. we had to subtract 5 form the original n terms

 

[sarzkhan]

i think we had to subtract 5:s
im not sure about that.

 

[1357913579]

and difference for ap was 3 iam not sure but wasnt A=-15

 

[Abdulrab]

i think the ratio answer was 3 :1 because my answer was 3(3)^0.5 and 1(3)^0.5 in which (3)^0.5 means under root 3 !!! :S please reply guys

 

[phro5031]

the range of sinx and cos2x must be between 0 and 180 , you must put the ends where it has to start with 0 to 30 and from 150 to 180