maths p1....

[hassam]

6 sin2x-3=0......i get smallest value in range 0-2pi......-11pi/12....bt ms says sumthin else....

 

[msk]

see u first change the range! btw what is the range of question?
any way 6sin2x=3
2x=(sin inverse 3/6)
2x= pi/6
x= pi/12 this is your first value second value depends upon your range!

 

[rz123]

the first three terms in the expansion of (2+ax)^n , in ascending powers of x, are 32-40x+bx^2. find the value of the constants n, a and b. may/june 2006 p1
plz tell me how is b constant calculated.

 

[hassam]

oh it was 6 sin(2x)+3=0