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Maths Paper 42 2013

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how do you solve transformation questions where they ask you to write down the 2*2 matrix representing a transformation
 
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i) 6/8 x 5/7 x 4/6 = 5/7 ... as it is without replacement so total number decreases each time.
ii) (2/8 x 6/7 x 5/6) + (6/8 x 2/7 x 5/6) + (6/8 x 5/7 x 2/6) = 5/28 ....the buttons can be picked in different ways...
b) x/25 x (x-1)/24 = 7/100 ...as there is no replacement both values will be -1
when you solve you get... 600x2 - 600x -4200 = 0 .. divide by 600 and you get..... x2 -x -42 =0
i'm assuming you can solve the rest of the question and i hope this helped :)
 
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As we all know, this paper will be very difficult due to the lack of hard questions in paper 2.
So the topics that are probably going to come are:
- Transformations
- Trigonometry, Mensuration..etc
- Matrices
- Inequalities and so on
Make sure you study those.

PS. Since it's probably going to be hard, does a total of 175/200 get an A*?
What about an A, at least how much should we get to get an A then? Overall in both ppr 2 & ppr 4? :)
 
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