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- Thread starter bamteck
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What difficulty do u have??bamteck said:Plz Plz Help ::

(i) 6

(ii) (a)Area of circle is nr^2....the diameter of the largecircles is equal to the 3 diameters of small circle .....hence find the radius...and then find the area!!

(b) find the total area of small circles ...find the difference b/w large circle area and total area of small ones!!this gives the left out part...if u notice there are 6 such regions similar to shaded one so if u divide the difference by 6 u will get the shaded area

i think u might be finding this part difficult!! hope u r clear with it now...i did nt give u the answer cuz u shud try it on ur own!!I can help u but its always better to it urself

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Remember...the shortest distannce is always the perpendicular distance!!bamteck said:For this one, I need only to know the (a) (iii) the shortest distance from C to BD

& part (b) The greatest angle of depression..

Plzzzzz

so then u can use the trignometric ratios....in this case sin0 = opp/hyp...and find opp when hyp = 1040 and 0= 42 degrees!!

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the shortest distance from C to BD is the perp. distance from C to BD. Since u knowangle CBD and BC, the answer would be: sin 42= x/1040.

The greatest angle of depression would occur where the perpendicular distance from C to BD is shortest. So tan x =500/perp. distance found in (a) (iii).

Hope this helps

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vol.of hollow cylinder = (pi) x h x (R^2 - r^2)

Where R is the radius of big circle and r is the radius of small circle.....so R = r + 1.5

since we know vol. as 500...R=1.5 + r .....h = 6 solve the equation!!

500 = (pi) x 6 x [(1.5 + r)^2 - r^2]

500/[6(pi)] = r^2 + 3r + 2.25 - r^2

500/[6(pi)] = 3r + 2.25

r = 8.0919 = 8.09

Note...(r + 1.5 ) ^2 = r^2 + 3r + 2.25 ....[recall expanding (a + b)^2

Actually i havent understand what Uxair has done...but i'm quite sure my answer and method is correct!!

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(ii) then write the point where te line intersects the graph....

(iii) equate both the eqns. ....the eqn of curve = 1/2 x + 3

and simpligy to make it in the form required...

hope u understood