Need help with Maths(o level).

[musiclover gurl]

Can someone help me with this question, plzz?
In the diagram, the points P and Q lie on the sides BC and AC of triangle ABC.
AB is parallel to QP.
AQ = 2 cm and QC = 4 cm.
The area of triangle CPQ is 6 cm2.
Find the area of
(a) triangle AQP [1]
(b) triangle ABC[1]
(c) triangle ABP [1]


(Its a nov 2012 paper 1 question)

 

[Dark Destination]

Can someone help me with this question, plzz?
In the diagram, the points P and Q lie on the sides BC and AC of triangle ABC.
AB is parallel to QP.
AQ = 2 cm and QC = 4 cm.
The area of triangle CPQ is 6 cm2.
Find the area of
(a) triangle AQP [1]
(b) triangle ABC[1]
(c) triangle ABP [1]


(Its a nov 2012 paper 1 question)

(1) AQP and CPQ have a common height, so ratio of their areas will be equal to ratio of their bases.

Area of AQP = 2/4 x 6 = 3cm^2

(2) Triangle CPQ and ABC are similar, so ratio of their areas is equal to the square of the ratio of their sides.

(4/6)^2 = 6/x

And you can find x which is equal to 13.5 cm^2

(3) AQP was 3 cm^2 and CPQ is 6 cm^2. So subtract these from 13.5 to get 4.5cm^2.

 

[musiclover gurl]

(1) AQP and CPQ have a common height, so ratio of their areas will be equal to ratio of their bases.

Area of AQP = 2/4 x 6 = 3cm^2

(2) Triangle CPQ and ABC are similar, so ratio of their areas is equal to the square of the ratio of their sides.

(4/6)^2 = 6/x

And you can find x which is equal to 13.5 cm^2

(3) AQP was 3 cm^2 and CPQ is 6 cm^2. So subtract these from 13.5 to get 4.5cm^2.

Thanks a lot Dark Destination!

 

[Dark Destination]

Thanks a lot Dark Destination!

No problem

 

[zhaoyen56]

please help 😭