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NEXT UP: PHYSICS PAPER 3

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Questions, Notes, Tips, anything you might think would be useful please post them here! :D
 
R

rockincrew

this the physics syllabus
i think u have it and will be bored reading it so go to page 39-40 it has symbols and those thing stared u should know its definition
 
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yah dey r great bt dey dnt reallly hve evry thing...
guyz i reely need gud notes fr topics lyk reflection refraction nd stuff so cn u pleeeeeeeeezzz help me out ...:(
 
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im still not copletely satisfied with my preparation for electromagnetism,its the hardest topic for me to cover.....
 
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umm , did any one solved or tried to look at the Physics P31,32,33 O/N 2010 ...... these exams look different and seriously HARD =/ , what do u guys think??

howerver , does anyone has ALL the formulas we need to study ? in a document form if possible please

AND

If any one has some good and important points for this paper please share it , cause im kinda hopeless lol ....
 
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What do they mean from the Syllabus (0625) physics:
Section 4.3 (d) Digital electronics
Supplement
State and use the symbols for logic gates (candidates should use the American ANSI#Y 32.14 symbols).
And If anyone have useful Physics notes covering the whole Syllabus.
Thanks
 
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for physics just spam down as many past papers as you can...thats the best revision!
 
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AnnoyingCarrot123 said:
What do they mean from the Syllabus (0625) physics:
Section 4.3 (d) Digital electronics
Supplement
State and use the symbols for logic gates (candidates should use the American ANSI#Y 32.14 symbols).
And If anyone have useful Physics notes covering the whole Syllabus.
Thanks
they are the normal , symbols we use when drawing the different types of gates.
 
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R = ρl/A (ρ = resistivity of conductor at the temperature during experiment)

Previous resistance, R1 = V/I = 1.8/0.45 = 4 ohms = ρl1/A -- (1)

Temperature in 11(b) is the same, so ρ is same, but
diameter is halved, so new cross-sectional area = πr^2 = π(r/2)^2 = (πr^2) / 4 = A/4

Current resistance, R2 = V/I = 1.8 / 0.30 = 6 ohms = ρl2/(A/4) -- (2)

(2) / (1) : 6/4 = 4xl2/l1 => l2/l1 = 6/16 = 3/8

.: length of 2nd coil = 3/8ths length of old coil.
 
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ppl plzz i need help in the deflection of alpha particles and beta particles due to magnetic field and electric field !!!
PLLLLLLLLZZZZZZZZ
THX <:
 
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α- & β- particles are deflected in electric and magnetic fields due to their being charged. α-particles are +vely charged, and attracted to -ve plate, β-particles are -vely charged and attracted to the +ve plate. Deflections are towards said plates. Charges moving in a magnetic field = current ( or current = how fast charge moves ; 1 ampere = 1 coulomb passing a point per second ). Current induces magnetic field, the combined effect with another magnetic field resulting in a force on said current. Use Fleming's Left Hand rule to determine the direction of force / thrust. Direction of current is direction of +ve charge flow, or opposite to -ve charge flow.
 
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ChrisChin said:
ARE YOU GUYS READY FOR IT??? ^^ The hardest paper in IGCSE is almost at hand! ^^
uhhhhhh no not really!!
ive studies evrytin bt still vry nervous!
the past papers r a NIGHTMARE!
 
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