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Nuclear physics question..

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A nuclear reactor is fuelled by fission of uranium. The output from the reactor is 200 MW. The equation below describes a typical fission reaction:
BLA BLA I've done these parts moving on to the last part, which I'm unable to understand.

Q. Calculate the mass of uranium-235 that is required to run the reactor for 1 year.
(mass of u-235=3.90x10^(-25), 1 year =3.15x10^7)

Help please...
 
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http://postimage.org/image/dufbhoy2z/ < Question Image

Q4 Last part.
I didn't know how to type all that so :).
AoA,
In (ii) you found number of reactions occuring in 1 second!
lets suppose n reactions occur in each second, (n is your answer of (ii))
In 1 reaction, mass of uranium needed = 3.90 * 10^-25 kg s-1
In n reactions, mass of uranium needed = n * (3.90 * 10^-25) kg s-1

In one year there are 3.15 * 10^7 seconds
So,
mass of uranium needed = n * (3.90 * 10^-25) * 3.15 * 10^7 kg
 
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